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2 years ago

14

in a standard xy plane, a line passes through the points (n,8)(32,n) and the origin. if n is a positive real number, what is the

value of n

1 answer:

Igoryamba2 years ago

8 0

Answer:

n = 16

Step-by-step explanation:

The slope from the origin to each point must be equal

(0,0) and (n, 8)

m = 8/n

(0, 0) and (32, n)

m = n/32

Set the slopes equal

8/n = n/32

cross multiply

256 = n²

Take the square root of both sides

n = 16

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What is the most precise name for a quadrilateral with the following vertices:

pashok25 [27]

<h2>Therefore it is a parallelogram.</h2>

Step-by-step explanation:

Given the vertices of the quadrilateral are A(2,3) , B(7,2), C(6,-1) and D(1,0)

The length of AB is $=\sqrt{(2-7)^2+(3-2)^2}$ $=\sqrt{26}$ units

The length of BC is $=\sqrt{(7-6)^2+(2+1)^2}$ $=\sqrt{10}$ units

The length of CD is $=\sqrt{(6-1)^2+(-1-0)^2}$ $=\sqrt{26}$ units

The length of DA is $=\sqrt{(1-2)^2+(0-3)^2}$ $=\sqrt{10}$ units

The length of AC is $=\sqrt{(2-6)^2+(3+1)^2}$ $=4\sqrt{2}$ units

The length of BD is $=\sqrt{(7-1)^2+(2-0)^2}$ = $2\sqrt{10}$ units

Here length of AB = length of CD ,

length of BC= length of DA and

length of AC ≠ length of BD

In this quadrilateral, the opposite sides are equal but the diagonals are not equal

Therefore it is a parallelogram.

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3 years ago

ErvIn bowled 7 games last weekend. his scorers are : 155,165,138,172,193,142. what is the range of ErvIn scores

EastWind [94]

The range of Ervin's scores is 55.

Range is the difference between the largest number and the smallest number.

To find the range of a set of values, first sort the values numerically (smallest to largest). With this set, it would look like this: 138, 142, 155, 165, 172, 193. Lastly, subtract 138 from 193 to find the range. By doing so, you will get 55 as an answer.

I hope this helps!

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3 years ago

Find the standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8

Gekata [30.6K]

First, let $(x,y)$ be a point in our parabola. Since we know that the focus of our parabola is the point (0,8), we are going to use the distance formula to find the distance between the two points:
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Next, we are going to find the distance between the directrix and the point in our parabola. Remember that the distance between a point (x,y) of a parabola and its directrix, $y=c$ , is: $|y-c|$ . Since our directrix is y=-8, the distance to our point will be:
$|y-(-8)|$
$|y+8|$

Now, we are going to equate those two distances, and square them to get rid of the square root and the absolute value:
$\sqrt{(x-0)^{2}+(y-8)^{2}}=|y+8|$
$(\sqrt{(x-0)^{2}+(y-8)^{2}})^{2}=|y+8|^{2}$
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Finally, we can expand and solve for $y$ :
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3 years ago

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Irina18 [472]

Answer:

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Step-by-step explanation:

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3 years ago

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dimaraw [331]

Answer:

B.24

Step-by-step explanation:

we know,

exterior angle = 360°/n(where 'n' is number of sides)

then,

15° = 360°/n

n = 360°/15°

n = 24

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3 years ago