As AB is a diameter, then m∠CBA=180^{0}-75^{0}=105^{0}.
∠CBA is a central angle, so its measure multiplied by radius is the length of arc AC.
Note that
![105^{0}=7\cdot 15^0](https://tex.z-dn.net/?f=105%5E%7B0%7D%3D7%5Ccdot%2015%5E0)
and
![15^{0}= \frac{\pi}{12}](https://tex.z-dn.net/?f=15%5E%7B0%7D%3D%20%5Cfrac%7B%5Cpi%7D%7B12%7D%20)
. Then
![105^{0}= \frac{7\pi}{12} = \frac{7\cdot 3.14}{12}=1.83](https://tex.z-dn.net/?f=105%5E%7B0%7D%3D%20%5Cfrac%7B7%5Cpi%7D%7B12%7D%20%3D%20%5Cfrac%7B7%5Ccdot%203.14%7D%7B12%7D%3D1.83%20)
and length of the arc is
![12\cdot 1.83=21,96](https://tex.z-dn.net/?f=12%5Ccdot%201.83%3D21%2C96)
.The correct answer is 22 in.
Hi. Unfortunately there is no statement to determine if it's true or not. However, I would just give the correct statement.
Secant function is the inverse of cosine. In trigonometry, a right triangle has one 90 degrees angle. It consists of the hypotenuse(h), the adjacent side (a), and the opposite side(o), with respect to the angle. For cosine, it is adjacent over hypotenuse. Since secant is the inverse, it would be hypotenuse/adjacent. Hypotenuse is the longest side.
Hence, sec theta = 15/9
I hope this helps :)
Answer:
640 bacteria.
Step-by-step explanation:
Make a chart.
Bacteria Weeks
40 0
80 1
160 2
320 3
640 4
It starts off with 40 bacteria, which means no weeks have passed so far. That is why 40 pairs with 0 rather than 1.
By using the concept of Depreciation, it is obtained that
Warrem's body metabolize half of the 84 mg of caffeine in 4.71 hours
What is Depreciation?
Depreciation is the reduction in the value of a product at a certain rate over a certain period of time.
Here the concept of Depreciation has been used
Let the time taken to metabolize half of the 84 mg of caffeine be t hours
Damien's body metabolizes caffeine at a rate of 13.7% per hour
By the problem,
![84(1 - \frac{13.7}{100})^t = 42\\\\(1 - \frac{13.7}{100})^t = \frac{42}{84}\\\\(1 - \frac{13.7}{100})^t = \frac{1}{2}\\\\(\frac{100 -13.7}{100})^t = \frac{1}{2}\\\\(\frac{86.3}{100})^t = \frac{1}{2}\\\\(\frac{863}{1000})^t = \frac{1}{2}\\\\t(ln(\frac{863}{1000}) = -0.693\\\\-0.147t = -0.693\\\\t = \frac{0.693}{0.147}\\\\t = 4.71 \ hours](https://tex.z-dn.net/?f=84%281%20-%20%5Cfrac%7B13.7%7D%7B100%7D%29%5Et%20%3D%2042%5C%5C%5C%5C%281%20-%20%5Cfrac%7B13.7%7D%7B100%7D%29%5Et%20%3D%20%5Cfrac%7B42%7D%7B84%7D%5C%5C%5C%5C%281%20-%20%5Cfrac%7B13.7%7D%7B100%7D%29%5Et%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%28%5Cfrac%7B100%20-13.7%7D%7B100%7D%29%5Et%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%28%5Cfrac%7B86.3%7D%7B100%7D%29%5Et%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%28%5Cfrac%7B863%7D%7B1000%7D%29%5Et%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5Ct%28ln%28%5Cfrac%7B863%7D%7B1000%7D%29%20%3D%20-0.693%5C%5C%5C%5C-0.147t%20%3D%20-0.693%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7B0.693%7D%7B0.147%7D%5C%5C%5C%5Ct%20%3D%204.71%20%5C%20hours)
To learn more about Depreciation, refer to the link-
brainly.com/question/25806993
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