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soldi70 [24.7K]
2 years ago
8

Which fraction represents the shaded part of the grid?

Mathematics
2 answers:
elena-14-01-66 [18.8K]2 years ago
8 0

Answer:

3 tenth or 3/10 or 30%

Step-by-step explanation:

all works :)

Alexxandr [17]2 years ago
5 0

Answer:

30%

Step-by-step explanation:

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Pls help !<br> i need help with all 3 questions quick
Zarrin [17]

Ask your mummy......

6 0
3 years ago
The temperature went from -12°F to 18°F. How much did the temperature change
vlada-n [284]

Answer:

18 - (-12)

Step-by-step explanation:

Final temp. - Initial temp. = the change in temperature

By -12, we're indicating that is below zero (which is obvious) meaning that it is not in the "normal" scale nor in the imaginary scale of numbers. So, we can operate the following...

18 - (-12) = 30

So the temperature changed by 30 values or the temperature increased by 30 values, because the number is positive.

6 0
2 years ago
9 meters of gold wire. How long is the wire in millimeters?
kenny6666 [7]
Milli means 1000
1 meter=1000 milimeters

therefor
9 times 1 meter=9 times 1000 milimeters
9 meter=9000 milimeters
6 0
3 years ago
Read 2 more answers
Let T:V→W be a linear transformation from a vector space V into a vector space W. Prove that the range of T is a subspace of W.
9966 [12]

Answer:

The range of T is a subspace of W.

Step-by-step explanation:

we have T:V→W

This is a linear transformation from V to W

we are required to prove that the range of T is a subspace of W

0 is a vector in range , u and v are two vectors in range T

T = T(V) = {T(v)║v∈V}

{w∈W≡v∈V such that T(w) = V}

T(0) = T(0ⁿ)

0 is  Zero in V

0ⁿ  is zero vector in W

T(V) is not an empty subset of W

w₁, w₂   ∈ T(v)

(v₁, v₂ ∈V)

from here we have that

T(v₁) = w₁

T(v₂) = w₂

t(v₁) + t(v₂) = w₁+w₂

v₁,v₂∈V

v₁+v₂∈V

with a scalar ∝

T(∝v) = ∝T(v)

such that

T(∝v) ∈T(v)

so we have that T(v) is a subspace of W. The range of T is a subspace of W.

8 0
3 years ago
In figure AB and CD bisect each other at O. State the 3 pairs of equal parts in ∆AOC and ∆BOD. Is ∆AOC ≅ ∆BOD? Give reasons
GuDViN [60]

Answer:

SEE EXPLANATION

Step-by-step explanation:

In\:\triangle AOC \:\&\:\triangle BOD

AO \cong OB.... (given)

\angle AOC \cong\angle BOD

(vertical \: \angle s)

CO \cong OD.... (given)

\therefore \triangle AOC \:\cong\:\triangle BOD

(SAS \: postulate)

So, the 3 pairs of equal parts in ∆AOC and ∆BOD are:

AC = BD

m\angle OAC = m\angle OBD

m\angle OCA = m\angle ODB

7 0
3 years ago
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