Given a quadratic function
y = 4x² - 19x - 5
or i will write it as
4x² - 19x - 5 = y
Zero of the function is when y have the value of zero.
So the quadratic equation will be
4x² - 19x - 5 = y
4x² - 19x - 5 = 0
Now make the equation to intercept form by factorization
4x² - 19x - 5 = 0
(4x + 1)(x - 5) = 0 (this is intercept form)
Solution 1
4x + 1 = 0
4x = -1
x = -1/4
Solution 2
x - 5 = 0
x = 5
SUMMARY
-1/4 and 5 are zero function of f(x) = 4x² - 19x - 5
Answer:
The transversals cutting through the parallel lines create angles that are congruent to one another. Angles 1`and 5 are alternate interior and are congruent. Angles 2 and 6 are alternate interior and are congruent. And of course if 2 of 3 angles in 2 triangles are congruent, then the 3rd angles have to be congruent as well. HOWEVER, we can see that the sides are NOT congruent, and we need at least one side to prove congruency. Since we have 3 congruent angles, we can only say they are similar.
Step-by-step explanation:
19) 15/a = 3/2
Start by cross multiplying....
3a = 30
Divide both sides 3
a = 10
21) 2/7 = 4/d
2d = 28
d= 14
23) 8/p = 3/10
80 = 3p
p = 26.66
25) 2 / -5 = 6/t
2t = -30
t = -15
Answer:
9
Step-by-step explanation:
