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Sphinxa [80]
3 years ago
11

3.625 x 10−4 Question 2 options: .3625 36,250 0.0003625

Mathematics
1 answer:
disa [49]3 years ago
3 0

Answer:

0.0003625

:) Hope that helps :)

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Explain how you could use either of two operation to solve exercise 10.
zheka24 [161]
You want to know the factor by which 3 2/3 is multiplied to get 7 1/3.

1. You can estimate that it is 2 from 7/3 ≈ 2, then check by multiplication to see if that is right.
.. 2*(3 2/3) = 6 4/3 = 7 1/3 . . . . 2 is the correct factor.

2. You can divide 7 1/3 by 3 2/3 to see what the factor is.
.. (7 1/3)/(3 2/3) = (22/3)/(11/3) = 22/11 = 2 . . . . 2 is the factor Earl used.

3. You could see how many times you can subtract 3 2/3 from 7 1/3.
.. 7 1/3 -3 2/3 = (7 -3) +(1/3 -2/3) = 4 -1/3 = 3 2/3 . . . . . subtracting once gives 3 2/3
.. 3 2/3 -3 2/3 = 0 . . . . . . subtracting twice gives 0, so the factor is 2.

4. You could add 3 2/3 to see how many times it takes to get 7 1/3.
.. 3 2/3 +3 2/3 = (3 +3) +(2/3 +2/3) = 6 +4/3 = 7 1/3
We only need to add two values of 3 2/3 to get 7 1/3, so the factor is 2.

___
We have shown methods using multiplication, division, subtraction, addition. Take your pick.
3 0
3 years ago
Lee pays $72 in advance on his account at the movie store. Every time he rents a movie, $4 is deducted from his account for ever
lapo4ka [179]
So it would be,
y = 72 - 4x
y is the total money that is left on the account and x isthe movies rented. after renting 4 movies it would be,

y = 72 - 4(4)
y = 72 - 16
y = 56

So there are $56 left in the account after renting 4 movies.
3 0
4 years ago
On one day a pet store sells 2 birds 6 gerbils 3 fish and 3 hamsters whats the data and relative frequency as a percent?
bonufazy [111]

Answer:

Birds F_b=14.3\%

Gerbils F_g=42.9\%

Fish F_f=21.4\%

Hamsters F_h=21.4\%

Step-by-step explanation:

From the question we are told that:

Sales

Number of birds  n_b=2

Number of gerbils  n_g=6

Number of fish  n_f=3

Number of hamsters  n_h=3  

Generally the frequency for birds F_b is mathematically given b

F_b=\frac{n_b}{n}*100

F_b=\frac{2}{14}*100

F_b=14.3\%

Generally the frequency for Gerbils F_g is mathematically given b

F_g=\frac{n_g}{n}*100

F_g=\frac{6}{14}*100

F_g=42.9\%

Generally the frequency for fish F_f is mathematically given b

F_f=\frac{n_f}{n}*100

F_f=\frac{3}{14}*100

F_f=21.4\%

Generally the frequency for fish F_h is mathematically given b

F_h=\frac{n_h}{n}*100

F_h=\frac{3}{14}*100

F_h=21.4\%

5 0
3 years ago
The m∠B is two more than three times the measure of ∠C. If ∠B and ∠C are complementary angles, find the measures of both angles.
allsm [11]

Answer:

B = 68°  and  C = 22°

Step-by-step explanation:

Let angle B's measure be B and angle C's measure be C.

Also note that complementary means that they sum to 90.

Now:

<u>The m∠B is two more than three times the measure of ∠C:</u>

we can write:

B = 3C + 2

<u>If ∠B and ∠C are complementary angles:</u>

B + C = 90

Putting 1st equation in 2nd, we get:

B + C = 90

3C + 2 + C = 90

4C = 90 - 2

4C = 88

C = 88/4 = 22

Now B = 3C + 2, so

B = 3(22) + 2 = 68

Hence, B = 68 degrees and C = 22 degrees

7 0
3 years ago
Which type of symmetry does this figure have?
Karolina [17]

Answer:

reflection and rotation

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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