Hi! Basically, the problem is asking us to find the values of a, b, and c in the equation

. Since we have three unknowns, we just need three equations. We can find these equations by using the data in the table.
First let's plug x = 0 and f(x) = 0.


Now that we know c, it's time to pick two more pairs. Let's plug-in (2,78) and (4,152)


Before proceeding with the process of eliminating one variable, let us first reduce both equations to their lowest terms. We divide the first equation by 2 and we divide the second one by 4.


Next, we subtract equation 2 from equation 1.


Finally, we substitute the value of a to equation 2 to get the value of b.


Therefore, the function should be