Question

Evaluat 1/2^-2x^-3y^5 for x=2 and y=-4

Answer 1

Answer:

-1/32

Step-by-step explanation:

1/(2⁻²x⁻³y⁵)

x=2

y=-4

1/(2⁻²x⁻³y⁵)  = 1/(2⁻²2⁻³-4⁵)  

4= 2²

equate it back where 4 is

1/(2⁻²2⁻³2²⁽⁵⁾)  = 1/(2⁻²2⁻³2¹⁰)

using law of indices

1/(2⁻²⁺⁽⁻³⁾+¹⁰)  = 1/(2⁻²⁻³⁺¹⁰) = 1/2⁻⁵⁺¹⁰= 1/2⁻⁵ = -1/2x2x2x2x2 = -1/32

Answer 2

Answer:

$-\frac{1}{32}$

Step-by-step explanation:

Given Equation:

$\frac{1}{2^-^2*x^-^3*y^5}$

Multiplying numerator and denominator by $2^2*x^3$ gives:

       $\frac{2^2*x^3}{y^5}$

We have to evaluate the equation at $x=2 and y=-4$

Putting the values of x and y in the equation:

           =  $\frac{2^2*2^3}{(-4)^5}$

         = $\frac{4*8}{(-1024)}$

         = $-\frac{32}{1024}$

          =  $-\frac{1}{32}$

On putting the value of 'x' and 'y' in the equation the solution of the equation is $-\frac{1}{32}$