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sasho [114]
3 years ago
5

Find the unit rate please and thank you...

Mathematics
2 answers:
Gnom [1K]3 years ago
8 0

Answer:

the unit rate is 1/10.

Step-by-step explanation:

4/40 divided by 4 equals 1/10

Lady bird [3.3K]3 years ago
8 0

unit rate is 0.1 tickets per dollar

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Which of the following theorems verifies that LMN = ABC
SpyIntel [72]

Answer:

D. LA

Step-by-step explanation:

The diagram shows two right triangles having a corresponding acute angle each which are congruent to each other. Also, the leg in ∆LMN is also congruent to the corresponding leg in ∆ABC.

This satisfy the LA Congruence Theorem. Therefore, both triangles are congruent based on the LA congreunce theorem.

4 0
3 years ago
A rectangular yard is enclosed by 100 meters of fencing. The table shows some possible values for the length and width of the ya
Kryger [21]
10 40 400
20 30 600
25 25 625
35 15 525
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5 0
3 years ago
10. In a survey of 212 people at the local track and field championship, 72% favored the home team
igomit [66]

Answer:

a. The margin of error for the survey is of 0.0308 = 3.08%.

b. The 95% confidence interval that is likely to contain the exact percent of all people who favor the home team winning is (65.96%, 78.04%).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error of the survey is:

M = \sqrt{\frac{\pi(1-\pi)}{n}}

The confidence interval can be written as:

\pi \pm zM

In a survey of 212 people at the local track and field championship, 72% favored the home team winning.

This means that n = 212, \pi = 0.72

a. Find the margin of error for the survey.

M = \sqrt{\frac{0.72*0.28}{212}} = 0.0308

The margin of error for the survey is of 0.0308 = 3.08%.

b. Give the 95% confidence interval that is likely to contain the exact percent of all people who favor the home team winning.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Lower bound:

\pi - zM = 0.72 - 1.96*0.0308 = 0.6596

Upper bound:

\pi + zM = 0.72 + 1.96*0.0308 = 0.7804

As percent:

0.6596*100% = 65.96%

0.7804*100% = 78.04%.

The 95% confidence interval that is likely to contain the exact percent of all people who favor the home team winning is (65.96%, 78.04%).

7 0
3 years ago
(-10,2) (-5,-1) find mid point
zmey [24]

The Mid - point of the line segment is at coordinates -  M(- 7.5, 0.5)

We have two coordinate points -  A(- 10, 2)  and  B(- 5, -1)

We have to find the midpoint of this line AB.

<h3>What is Mid - Point Theorem?</h3>

It states that a line with endpoint coordinates as - (x_{1} ,y_{1} ) and (x_{2} ,y_{2} ) has its mid - point at the coordinates -

(x_{M} ,y_{M} ) =( \frac{x_{1} +x_{2} }{2} , \frac{(y_{1} +y_{2} )}{2} )

According to question, we have -

First coordinate Point -  (x_{1} ,y_{1} ) = (- 10, 2)

Second coordinate Point - (x_{2} ,y_{2} ) = (- 5, - 1)

Using the Mid - Point formula, we get -

(x_{M} ,y_{M} ) =( \frac{x_{1} +x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) =

x_{M} = \frac{-10-5}{2} = \frac{-15}{2} = - 7.5\\\\y_{M} = \frac{2 - 1}{2}  = \frac{1}{2} = 0.5

Hence, the Mid - point of the line segment is at coordinates -

M(- 7.5, 0.5)

To solve more questions on Mid - points, visit the link below -

brainly.com/question/25377004

#SPJ1

5 0
1 year ago
Which of the following completes the rule for this translation, (x, y) → (x − 8, ___)?
almond37 [142]

Answer:

The answer would be c

Step-by-step explanation:

I did it edge yesterday

4 0
3 years ago
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