Answer: 15(30 +33) = 945
Step-by-step explanation:
First, you have to distribute the 63 and make it smaller to become 30 + 33. So, the equation would be 15(30 + 33) = 450 + 495 = 945
Answer:
762 days
Step-by-step explanation:
Given

Let the rate be R.
So the rate change with time is represented as:

So:

To get the number of insects between day 0 and day 3, we need to integrate dR and set the bounds to 0 and 3
i.e.
becomes


Integrate
![R = 200t + \frac{10t^2}{2} + \frac{13t^3}{3} [3,0]](https://tex.z-dn.net/?f=R%20%3D%20200t%20%2B%20%5Cfrac%7B10t%5E2%7D%7B2%7D%20%2B%20%5Cfrac%7B13t%5E3%7D%7B3%7D%20%5B3%2C0%5D)
Solve for R by substituting 0 and 3 for t





<em>The population of insect between the required interval is 762</em>
5 small milkshake outcomes
5 medium milkshake outcomes
and
5 large milkshake outcomes
since there are only 5 flavors you can only make 5 different milkshakes unless you want to mix the flavors to make
5+10= 15 so you could make 15 that mixing each ice cream with each other and then mixing all of them.
Answer:
y=-7x-22
Step-by-step explanation:
y-y1=m(x-x1)
y-6=-7(x-(-4))
y-6=-7(x+4)
y=-7x-28+6
y=-7x-22
Please mark me as Brainliest if you're satisfied with the answer.