V(S)=S^3/6
S=6
V(6)=6^3/6=6^2=36
Answer:
Step-by-step explanation:
This is already factored for us, which is really nice, so now all we need to do is apply the Zero Product Property to the sets of parenthesis and solve for x, which will give us the 2 times that the object is on the ground.
x + 1 = 0 so
x = -1
x - 9 = 0 so
x = 9
We all know that time cannot ever be negative, so the time that the object is on the ground is 9 seconds after it's launched (which was from an initial height of 45 meters).
Answer:(3x + 7) (x +5)
Step-by-step explanation:
Answer:
The answer is 9 days
Step-by-step explanation:
First, we realise
-1.F = 1 day
-9.F = 9 days
The -1.F times 9 gives us one so the days times 9 as well.
Answer = 9
Answer:
7. Distributive Property
8. 8x +2.5
Step-by-step explanation:
7. The equation matches the pattern ...
a(b + c) = ab + ac . . . . . . . statement of Distributive Property
with a=√2, b=5, c=4
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8. The one-time charge of 2.50 will appear added in the equation one time (and not multiplied by anything). The number of tickets (x) will be multiplied by the ticket charge (8) and added to the one-time charge. Only one answer choice does that:
8x + 2.5
