Question

Loud speaker A vibrates 200 times each second. Loud speaker B vibrates 400 times each second.a)What is the frequency of the sound produced by Loud speaker A ? Give the value and unit.
b)Which loudspeaker produces higher frequency of vibrations?
(Show calculations)

Answer 1

Answer:

For a: The frequency produced by loudspeaker A is 200 Hz

For b: Loudspeaker B produces a higher frequency of vibrations.

Explanation:

To calculate the frequency of a loudspeaker, we use the formula:

$\nu=\frac{\text{Number of vibrations}}{\text{Time period}}$          ......(1)

where,

$\nu$ = frequency

• For loudspeaker A:

Number of vibrations = 200

Time period =  1 second

Putting values in equation 1:

$\nu_A=\frac{200}{1s}=200Hz$

• For loudspeaker B:

Number of vibrations = 400

Time period =  1 second

Putting values in equation 1:

$\nu_B=\frac{400}{1s}=400Hz$

Hence, the frequency produced by loudspeaker A is 200 Hz and loudspeaker B produces a higher frequency of vibrations.