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Ilia_Sergeevich [38]
4 years ago
11

Assume 3 molecules of Fe react according to the following equation. 3Fe + 4H2O Fe3O4 + 4H2 How many molecules of H2 are produced

? How many water molecules are required? What is the mole ratio of Fe to H2O? How many hydrogen molecules (H2) are involved in this reaction?
Chemistry
2 answers:
user100 [1]4 years ago
6 0

How many molecules of H2 are produced?: 4 molecules

How many water molecules are required?: 4 molecules

What is the mole ratio of Fe to H2O?: 3/4

How many hydrogen molecules (H2) are involved in this reaction?: 4 molecules

Wewaii [24]4 years ago
5 0
Chemical reaction:  3Fe + 4H₂O → Fe₃O₄ + 4H₂<span>.
From chemical reaction:
1) n(Fe) : n(H</span>₂) = 3 : 4.
Four molecules of hydrogen are produced.
2) n(Fe) : n(H₂O) = 3 : 4.
Four molecules of water are required, because the mole ratio of Fe to H₂O is 3:4.
3) Hydrogen molecules are not<span> involved in this reaction, but produced (4 molecules).</span>
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How many joules of heat are required to raise the temperature of 320.0 grams of water from 24.2°C to 50.8°C? Heat capacity of wa
balu736 [363]

Answer:

35750.4 Joules

Explanation:

Using the formula as follows;

Q = m × c × ∆T

Where;

Q = amount of heat (joules)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

According to the provided information,

mass (m) = 320.0 grams

c = 4.2 J/g°C

∆T = (50.8°C - 24.2°C) = 26.6°C

Q = ?

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2 years ago
If a 45 mM phosphate solution(solution A) had an absorbance of 1.012. What would be the absorbance if 11 mL of solution A was us
timofeeve [1]

Answer:

0.550

Explanation:

The absorbance (A) of a substance depends on its concentration (c) according to Beer-Lambert law.

A = ε . <em>l</em> . c

where,

ε: absorptivity of the species

<em>l</em>: optical path length

A 45 mM phosphate solution (solution A) had an absorbance of 1.012.

A = ε . <em>l</em> . c

1.012 = ε . <em>l</em> . 45 mM

ε . <em>l</em>  = 0.022 mM⁻¹

We can find the concentration of the second solution using the dilution rule.

C₁ . V₁ = C₂ . V₂

45mM . 11mL = C₂ . 20.0 mL

C₂ = 25 mM

The absorbance of the second solution is:

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