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Naddik [55]
3 years ago
15

Suppose there was a release of 1 mole of Alpha emission particle and 1 mole of Beta emission particles and both particles are ac

celerated to 20.50 MeV. What is the total energy in kJ/nuclei?
Chemistry
1 answer:
Vitek1552 [10]3 years ago
6 0

Answer:

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Explanation:

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How does soil form bare rock???
RSB [31]
Weathering and erosion produce ever smaller rock particles which,

when mixed with dust and decayed organic matter over time , 

result in different types of soil . 

[hope this helps]



3 0
3 years ago
Predict the geometry around the central atom in SO2- A) trigonal pyramidal B) tetrahedral C) octahedral D) trigonal planar E) tr
liubo4ka [24]

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

To calculate the hybridization of SO_2, we use the equation:

\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom  (S) = 6

N = number of monovalent atoms bonded to central atom  = 0

C = charge of cation  = 0

A = charge of anion = 0

Putting values in above equation, we get:

\text{Number of electron pair}=\frac{1}{2}[6]=3

The number of electron pair around the central metal atom are 3. This means that the hybridization will be sp^2 and the electronic geometry of the molecule will be trigonal planar.

Hence, the correct answer is Option D.

3 0
4 years ago
The concentrated sulfuric acid we use in the laboratory is 98.0% sulfuric acid by weight. Calculate the molality and molarity of
timama [110]

Answer : The molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

Solution : Given,

Density of solution = 1.83g/cm^3=1.83g/ml

Molar mass of sulfuric acid (solute) = 98.079 g/mole

98.0 % sulfuric acid by mass means that 98.0 gram of sulfuric acid is present in 100 g of solution.

Mass of sulfuric acid (solute) = 98.0 g

Mass of solution = 100 g

Mass of solvent = Mass of solution - Mass of solute = 100 - 98.0 = 2 g

First we have to calculate the volume of solution.

\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}=\frac{100g}{1.83g/ml}=54.64ml

Now we have to calculate the molarity of solution.

Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}=\frac{98.0g\times 1000}{98.079g/mole\times 54.64ml}=18.29mole/L

Now we have to calculate the molality of the solution.

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{98.0g\times 1000}{98.079g/mole\times 2g}=499.59mole/Kg

Therefore, the molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

7 0
3 years ago
An igneous rock that _____ is made of really small mineral crystals. A. cools rapidly B. crystallizes slowly C. undergoes extrem
Elina [12.6K]

Answer: An igneous rock that cools rapidly is made of really small mineral crystals.

Explanation:

The layers inside the earth are hot enough to melt a rock. The liquid or molten rock is known as magma.

When a molten rock cools and solidifies, it results in the formation of an igneous rock.

The slow cooling of magma will result in the formation of an igneous rock with large crystals. Whereas, rapid cooling of lava will result in the formation of an igneous rock with small crystals.

Thus, it can be concluded that an igneous rock that cools rapidly is made of really small mineral crystals.


6 0
4 years ago
What is the difference between pure and applied chemistry?
bekas [8.4K]

Answer:

Explanation:

The major difference between pure and applied chemistry is the purpose and intent of the study.

Pure chemistry deals with the study of matter, matter transformations, and interactions between the different materials of the world, for only the sake of gaining empirical knowledge about the various substances that exist in the world. It does not really seek to apply this knowledge to do anything industrial.

Applied chemistry is the study of chemistry with the aim of utilizing this knowledge to solve the various problems that man faces. This approach of study is not for knowledge sake alone, rather it is for industrial application

3 0
3 years ago
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