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3 years ago

14

Please help. What is the intermediate step in the form (x+a)^2=b as a result of completing the square for the following equation

?

1 answer:

nevsk [136]3 years ago

7 0

Step-by-step explanation:

It makes 2x^2-20-206=0

Find D

Then find X1 and X2

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A bag contains 8 yellow marbles and 6 blue marbles. What number of

PilotLPTM [1.2K]

A bag contains 8 yellow marbles and 6 blue marbles. what number of yellow marbles can you add to the bag so that the ratio of yellow to blue marbles is 2:1? YOU HAVE 8 YELLOW MARBLES SO BY ADDING 4 MORE YOU HAVE (8+4)=12.

8 0

3 years ago

The weights of items produced by a company are normally distributed with a mean of 4.5 ounces and a standard deviation of 0.3 ou

GalinKa [24]

Answer:

The right solution is:

(a) 0.8849

(b) 12.28%

(c) 4.9935

(d) 28004

Step-by-step explanation:

Given:

Mean,

= 4.5

Standard deviation,

= 0.3

(a)

P(x > 4.14)

As we know,

⇒ $z = \frac{4.14-4.5}{0.3}$

$=-1.20$

then,

⇒ $P(z>-1.20) = P(z$

$=0.8849$

(b)

P(4.8 < x < 5.04)

= $P(\frac{4.8-4.5}{0.3} < \frac{x-\mu}{\sigma} < \frac{5.04-4.5}{0.3} )$

= $P(1$

= $P(z$

= $0.9641 -0.8413$

= $0.1228$

or,

= $12.28$ (%)

(c)

P(x > x) = 0.05

z value will be,

= 1.645

⇒ $1.645 = \frac{x - 4.5}{0.3}$

$x = 4.9935$

(d)

P(x < 5.01)

⇒ $z = \frac{x- \mu}{\sigma}$

$=\frac{5.01-4.5}{0.3}$

$=1.7$

P(z < 1.70) = 0.9554

⇒ $n = \frac{27875}{0.9954}$

$=28004$

3 0

3 years ago

Aldo drives a truck for a soft drink company. His truck is filled with 15 ounce cans and 70 ounce bottles. Let c be the number o

professor190 [17]

Answer:

15c+70b $\leq$ 112000

Step-by-step explanation:

Truck could carry 7000 pounds.

There are 15 ounce cans and 70 ounce bottles.

There are 'c' number of 15 ounce cans and 'b' is the number of 70 ounce bottles.

So, C number of cans can carry 15C ounces

'b' number of bottles can carry 70b ounces

So, we can set up inequality as

15c+70b $\leq$ 112000

3 0

3 years ago

sweet t has 2 orange picks for every 5 green. I f there are 21 picks in all, how many picks are orange?

weeeeeb [17]

If there are 21 picks, 6 are orange

8 0

4 years ago

Read 2 more answers

In a large population, 60% of the people have been vaccinated. If 4 people are randomly selected, what is the probability that A

gulaghasi [49]

Answer:

0.9744 probability that AT LEAST ONE of them has been vaccinated

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have been vaccinated, or they have not. The probability of a person having been vaccinated is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

60% of the people have been vaccinated.

This means that $p = 0.6$

If 4 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated?

This is

$P(X \geq 1)$ when $n = 4$ .

We have that

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.6)^{0}.(0.4)^{4} = 0.0256$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0256 = 0.9744$

0.9744 probability that AT LEAST ONE of them has been vaccinated

5 0

3 years ago