How to solve system of equation from a table
1 answer:
Answer:
Look for the same entry in both (all) tables.
Step-by-step explanation:
We assume here that the system of equations consists of two equations in two variables. If there are more equations in more variables, the general approach is the same.
A "solution" to a system of equations is a set of variable values that satisfies all equations of the system simultaneously. A table for one equation will generally list sets of variable values that satisfy that equation. <em>When the same set of values appears in the table for each of the equations, then that set of values is the solution</em>.
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<u>Example</u>
The attachment shows tables for two equations:
- y = 2x
- y = x+3
Highlighted are the table entries that are the same for both equations. This is the solution to the system of equations. (x, y) = (3, 6) satisfies both equations:
- 6 = 2·3
- 6 = 3+3
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Answer:
The amount spent on the refrigerator is $ 800 .
Step-by-step explanation:
Given as :
The amount spent on television = $ 1600
Le The total amount in the account = $ A
so, The amount left in account after spent on television = $ A - $ 1600
The amount spent on refrigerator = × ( A - 1600 )
The amount left in his saving account = × A
Now, According to question
A - ( 1600 + × ( A - 1600 ) ) =
× A
Or, A - × A = 1600 +
× ( A - 1600 )
Or, × A = 1600 +
× A -
× 1600
or, × A -
× A = 1600 - 640
Or, × A = 960
or, × A = 960
∴ A =
I.e A = 3600
So, The amount in the saving account is $3600
∵ , The amount spent on refrigerator = × ( 3600 - 1600 )
Or, The amount spent on refrigerator = × 2000
I.e The amount spent on refrigerator = $ 800
Hence The amount spent on the refrigerator is $ 800 . Answer
Answer:
c
Step-by-step explanation:
Since the figures are similar then the ratios of corresponding sides are equal, that is
=
, substitute values
=
( cross- multiply )
10YZ = 230 ( divide both sides by 10 )
YZ = 23 → c