This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
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If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
We are given the equation of a line
y = -2x + 1
We have to find the value of y at three different values of x i.e. x = 0, -3 and 1
In order to find the value of y at any given x, simply replace x by that number.
So, for x=0, we will replace x by 0 to find the value of y. So y will be:
y = -2(0) + 1
y = 1
This can be expressed as an ordered pair as (0,1)
Similarly for x=-3, we get
y = -2(-3) + 1 = 6 + 1
y = 7
This can be expressed as an ordered pair as (-3, 7)
And, finally for x=1, we get:
y= -2(1) + 1 = -2 + 1
y = -1
This can be expressed as an ordered pair as (-1, -1)
Answer:
y= 5
Step-by-step explanation:
:)
Answer:
s = 2 cm
Step-by-step explanation:
Given the following data;
Area of equilateral triangle = √3 cm
Mathematically, the area of an equilateral triangle is given by the formula;
A = √3 * s²/4
Where, s represents the sides of length.
Substituting into the formula, we have;
√3 = √3 * s²/4
Dividing both sides by √3, we have;
1 = s²/4
Cross-multiplying, we have;
4 = s²
Taking the square root of both sides, we have;
s = √4
s = 2 cm
Capacity of tank in litres:
1x2x1.5=3m^3 or 3000 litres
Volume of concrete:
(0.1*1.5*1*2)+(0.1*1.5*2(0.1*2))*2)+(0.1*1.2*2.2)=0.3+0.66+0.264=1.224 m^3 of concrete
(Thickness x Depth x Width excluding the thickness of the wall x Two sides) + (Thickness x Depth x Length including the thickness of the wall on both sides x Two sides) + (Base slab dimensions)
