Write the following in terms of sine theta only. cotangent

1 answer:

6 0

I don’t exactly know what you’re asking, but cotangent = cosine/sine or another way of writing it is sine = cosine/cotangent

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One light-year equals 5.9 x 1012 miles. How many light-years are in 6.79

inna [77]

Option B

The number of light years in $6.79 \times 10^{16}$ miles is 11508 light years

<em><u>Solution:</u></em>

Given that,

One light-year equals 5.9 x 10^12 miles

Therefore,

$1 \text{ light year } = 5.9 \times 10^{12} \text{ miles }$

To find: Number of light years in $6.79 \times 10^{16}$ miles

Let "x" be the number of light years in $6.79 \times 10^{16}$ miles

Then number of light years in $6.79 \times 10^{16}$ miles can be found by dividing $6.79 \times 10^{16}$ miles by miles in 1 light year

$\text{Number of light years in } 6.79 \times 10^{16} miles = \frac{6.79 \times 10^{16}}{5.9 \times 10^{12}}\\\\\text{Use the law of exponent }\\\\\frac{a^m}{a^n} = a^{m-n}\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = \frac{6.79}{5.9} \times 10^{16-12}\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = 1.1508 \times 10^4\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = 11508$

Thus number of light years in $6.79 \times 10^{16}$ miles is 11508 light years

3 0

2 years ago

The graph of a system of equations is shown.

Brut [27]

Answer:

Step-by-step explanation:

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5 0

2 years ago

Angle c is inscribed in circle O. AB is a diameter of circle O. what is the radius of circle.

Llana [10]

Answer:

The value of radius is 7.5 units

Step-by-step explanation:

Given that a line that pass through the origin and form a triangle is a right-angle triangle. So in order to find the diameter/hypotenuse, you have to use Pythogaras Theorem :

${c}^{2} = {a}^{2} + {b}^{2}$