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Otrada [13]
3 years ago
15

What are the solutions to the equation 9x^2=49?

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0
9x^2 = 49
x^2 = 49/9
x^2 = 5.4444444
x1 = <span> <span> <span> 2.3333333333 </span> </span> </span>
x2 = <span> <span> - 2.3333333333
Answer is A

</span> </span>
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Answer:

  • A. segment A double prime B double prime = segment AB over 2

Step-by-step explanation:

<u>Triangle ABC with coordinates of:</u>

  • A = (-3, 3), B = (1, -3), C = (-3, -3)

<u>Translation (x + 2, y + 0), coordinates will be:</u>

  • A' = (-1, 3), B = ( 3, -3), C = (-1, -3)

<u>Dilation by a scale factor of 1/2 from the origin, coordinates will be:</u>

  • A'' = (-0.5, 1.5), B'' = (1.5, -1.5), C= (-0.5, -1.5)

<u>Let's find the length of AB and A''B'' using distance formula</u>

  • d = √(x2-x1)² + (y2 - y1)²
  • AB = √(1-(-3))² + (-3 -3)² = √4²+6² = √16+36 = √52 = 2√13
  • A''B'' = √(1.5 - (-0.5)) + (-1.5 - 1.5)² = √2²+3² = √13

<u>We see that </u>

  • AB = 2A''B''

<u>Now the answer options:</u>

A. segment A double prime B double prime = segment AB over 2

  • Correct

B. segment AB = segment A double prime B double prime over 2

  • Incorrect. Should be AB = A''B''*2

C. segment AB over segment A double prime B double prime = one half

  • Incorrect. Should be AB/A''B'' = 2

D. segment A double prime B double prime over segment AB = 2

  • Incorrect. Should be A''B''/AB = 1/2
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Find the value of this expression: sin 45 sin 15 . The second step =
Vitek1552 [10]

Given expression is sin(45)sin(15)

this expression best matches with left side of the formula:

2 sin(A) sin(B)= cos(A-B) - cos(A+B)

so we can plug given angles 45 and 15 there

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2 sin(45) sin(15)= cos(30) - cos(60)

sin(45) sin(15)= [cos(30) - cos(60)]/2

We are getting negative sign and cos in the solution while none of the given choices have same situation so answer will be none of them.


-----------

For cos(75)-cos(15), we will use formula:

\cos\left(A\right)-\cos\left(B\right)=-2\sin\left(\frac{A+B}{2}\right)\sin\left(\frac{A-B}{2}\right)

Now plug the given angles

\cos\left(75\right)-\cos\left(15\right)=-2\sin\left(\frac{75+15}{2}\right)\sin\left(\frac{75-15}{2}\right)

\cos\left(75\right)-\cos\left(15\right)=-2\sin\left(\frac{90}{2}\right)\sin\left(\frac{60}{2}\right)

\cos\left(75\right)-\cos\left(15\right)=-2\sin\left(45\right)\sin\left30\right)

Hence choice B is correct.

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3 years ago
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