10pm:
Abx: 10am/4pm/10pm
pain relief: 10am/2pm/6pm/10pm
water: 10am/1pm/4pm/7pm/10pm
Answer:
He will earn $140, my bad miss calculated...
Step-by-step explanation:
Its 140....
<span>dimensions of the nickel plated square base: x*x = x^2
height: y
dimensions of the 4 silver plated sides: xy each
dimensions of the nickel plated top: x^2
Volume = 30cm^3 = yx^2 => y = 30 / x^2
Cost of the sides: 4 * xy * $3
Cost ot the top and the bottom: 2 * x^2 * $1
Total cost: 12xy + 2x^2
replace y by 30/x^2
=> cost = 12x * (30/x^2) + 2x^2 = 360 / x + 2x^2
Minimum cost => d [cost] / dx = 0 = - 360/x^2 + 4x =0
=> 90/x^2 - x =0
=> 90 - x^3 = 0
=> x^3 = 90
=> x = ∛(90) = 4.48
=> y = 30 / (4.48)^2 = 1.49
Answer: base: 4.48 cm* 4.48 cm; height: 1.49 cm
</span>
In throwing a dice, there are 6 possible outcomes, namely 1, 2, 3, 4, 5 and 6.
P=(no. of favourable outcomes)/(no. of possible outcomes)
When we multiply the probability of an event with no. of trials, the we get the expected frequency of that event.
1) P(getting 1)=1/6
expected frequency of getting 1
=P(getting)1)×no. of trials
=1/6×600=100
But it is given that one is scored 200 times, so it makes a large difference from expected frequency, which is 100.
Therefore, the dice is not fair.
2) P(getting a tail)=0.3
estimate for the number of times the coin will land on a tail
=expected frequency of getting a tail
=P(getting a tail)×no. of trials
=0.3×150=45
3)P(getting a six)=2/3
expected frequency of getting a six
=P(getting a six)×no. of trials
=2/3×300=200
4)P(getting a three)=0.5
expected frequency of getting a three
=P(getting a three)×350
=0.5×350=175
Because of the transversal and the parallel lines, we know that A+B=180°.
So:
5x + 20 + 9x - 92 = 180
14x - 72 = 180
14x = 180 + 72
14x = 252
x = 252/14
x = 18
A = 5x + 20
A = 5*18 + 20
A = 90 + 20 = 110
(Let’s check:
B = 9*18 - 92
B = 162 - 92
B = 70
70 + 110 = 180)