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Blababa [14]
3 years ago
15

WILL MARK BRAINLIEST

Mathematics
2 answers:
ozzi3 years ago
4 0

Answer:

1 sample

Step-by-step explanation:

There is only one sample given for 20%

Olenka [21]3 years ago
3 0

Answer:

the answer would be

b) 1 sample

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4[24-3(7x+6)]-6(4-14x)
garik1379 [7]

Answer:

0

Step-by-step explanation:

4[24-3(7x+6)]-6(4-14x)

4(24-21x-18)-24+84x

96-84x-72-24+84x

96-72-24-84x+84x

0 + 0

0

5 0
3 years ago
Read 2 more answers
Which linear equation is written in slope-intercept form?
bekas [8.4K]

Answer:

Where is the question. and answer choices

5 0
3 years ago
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Which equation represents the line through (0,0) and (3, 4)?
Burka [1]

Answer:

y=4/3x

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(4-0)/(3-0)

m=4/3

y-y1=m(x-x1)

y-0=4/3(x-0)

y=4/3(x)

y=4/3x

7 0
3 years ago
Assume you are given a boolean variable named isRectangular and a 2-dimensional array that has has been created and assigned to
Savatey [412]

Answer:

nElements = 0;

for (int i = 0; i < a2d.length; i++)

nElements += a2d[i].length;

isRectangular = true;

for (int i = 1; i < a2d.length && isRectangular; i++)

if (a2d[i].length != a2d[0].length)

isRectangular = false;

Step-by-step explanation:

2 dimensional array is created and  initialize element with 0. and the taking loop for 2 dimensional array .such as

n Elements = 0;

for (int i = 0; i < a2d.length; i++)

n Elements += a2d[i].length;

A boolean variable isRectangular and 2 dimensional array has been created if rectangle is true the take a2d.length and isRectangular less than i and intiliaze i with 1 then increment the i .It will give true value.

If rectangular is false then  apply if statement  and see if a2d[i] is not equal to a2d[0]

if (a2d[i].length != a2d[0].length)

isRectangular = false;

4 0
4 years ago
Why is 4r + 5 = 3 not an algebraic expression?
saw5 [17]

4r + 5 = 3 is not an algebraic expression because expressions are basically equations but WITHOUT answers. In this equation, 3 is shown as the answer, which makes it an equation, not an expression.

Hope this helps! Please correct me if I'm wrong! :D

6 0
3 years ago
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