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7nadin3 [17]
3 years ago
13

Plz helppppp asappppppp​

Mathematics
2 answers:
olchik [2.2K]3 years ago
7 0
Ok so the rectangle is 12x6 which is 72. The entire top part is 18 which means the other triangle side is 6. 6x6 = 36 so 72+36 is 108
Lesechka [4]3 years ago
3 0
Easy!

Okay, just add both areas!
12x6=72
6x6/2= 18

72+18=90km
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How many different 2-digit numbers are there with the following property:the tenth digit is greater than the units digit?
Serggg [28]

Answer:

45

Step-by-step explanation:

Simply start by listing out the numbers from smallest to largest.

We start out with the smallest number following this information being the number 10. The next are 21 and 20. The next are 32, 31, and 30. We can start to see a pattern. If the ten's digit is n, then there are n numbers within that ten-group that have a greater 10's digit than unit's digit. The largest ten-group (90 to 98) has 9 integers following the rules established. Thus, the number of 2-digit integers that have ten's digits greater than units digit is 1+2+3+...+9=45

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2 years ago
For each sequence, find the first 4 terms and the 10th term.<br> a) 3n + 4<br> b) 4n-5
Studentka2010 [4]

Answer:

see explanation

Step-by-step explanation:

To find the first 4 terms substitute n = 1, 2, 3, 4 into the formula, that is

(a)

a₁ = 3(1) + 4 = 3 + 4 = 7

a₂ = 3(2) + 4 = 6 + 4 = 10

a₃ = 3(3) + 4 = 9 + 4 = 13

a₄ = 3(4) + 4 = 12 + 4 = 16

Similarly substitute n = 10 for tenth term

a₁₀ = 3(10) + 4 = 30 + 4 = 34

(b)

a₁ = 4(1) - 5 = 4 - 5 = - 1

a₂ = 4(2) - 5 = 8 - 5 = 3

a₃ = 4(3) - 5 = 12 - 5 = 7

a₄ = 4(4) - 5 = 16 - 5 = 11, and

a₁₀ = 4(10) - 5 = 40 - 5 = 35

5 0
3 years ago
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ratelena [41]

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$87.99 is the total

3 0
3 years ago
Read 2 more answers
25 points
lbvjy [14]

Answer:

unit_4_study_guide_solutions.pdf

Step-by-step explanation:

This link is a study guide, and on the LAST PAGE it has the answer to your question!

4 0
4 years ago
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