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3 years ago

6

A model length of 12 cm. represents an actual length of 102 ft.the model has a width of 48cm. What is the width of the actual ob

ject?

1 answer:

Elodia [21]3 years ago

8 0

the answer would be 408

just set it up like this

12 48

---- = ----

102 ?

12*4=48 so 102*4 = 408

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Which expressions are equivalent to 2(2x + 4y + x − 2y)?

joja [24]

Answer: 2(3x + 2y) and 6x + 4y

Step-by-step explanation:

Hi, to answer this question we have to solve the expression.

2(2x + 4y + x − 2y)

First we have to simplify the expression within the brackets.

2 (2x + x +4y -2y)

2( 3x + 2y)

We have the first equivalent expression. Now to obtain the second expression we apply distributive property:

2 (3x) + 2 ( 2y)

6x + 4y

In conclusion 2(3x + 2y) and 6x + 4y are equivalent expressions to 2(2x + 4y + x − 2y).

Feel free to ask for more if it´s necessary or if you did not understand something.

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2 years ago

Solve for x.<br> 79<br> (8x - 4)<br> 3<br> -(3x + 17)

Liono4ka [1.6K]

Answer:

-2.4

Step-by-step explanation:

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2 years ago

I need help with this problem

erik [133]

I think the answer is 400 square centimetres

8 0

2 years ago

Solve 3 - x= -9.<br> O A. x= 6<br> O B. x= 12<br> O c. x= -6<br> O D. x=-12

Katarina [22]

Answer:

x=12

Step-by-step explanation:

you need the x alone so you substract 3 from both sides.

Then you have, -x= -12

You need the x positive so you change the sign for it but as it is an equation you need to do the same thing on the other side, making both sides positive.

x=12

6 0

2 years ago

Read 2 more answers

An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con

natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

$L = 3w --- (1)volume = l \times w \times h \\ \\ 88 = (3w) \times w \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\$

The construction cost now is:

$C = 4(l \times w) + 2 ( w \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}$

Now, to determine the minimum cost:

$\dfrac{dC}{dw}= 0 \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}$

$w = \dfrac{88}{3(3)}^{1/3} \ feet$

Now;

$length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet$

$height = ( 88})^{1/3} (3)^{1/3} \ feet$

6 0

2 years ago