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alukav5142 [94]

3 years ago

15

A $1,200 computer is losing value at a rate of 22% per year; 2 years

1 answer:

zalisa [80]3 years ago

6 0

Answer:

$730.08

Step-by-step explanation:

22% = 0.22

1 - 0.22 = 0.78

Value after 2 years

v = 1200(0.78)²

v = 730.08

$730.08

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Bingel [31]

Answer:

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Step-by-step explanation:

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3 years ago

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Solve for x: 4 over 5 x + 4 over 3 = 2x x = __________________ Write your answer as a fraction in simplest form. Use the "/" sym

alexgriva [62]

Let's see.

4x/5 + 4/3 = 2x

First we have to make each denominator the same, so I'll multiply 4x/5 by 3/3, 4/3 by 5/5, and 2x by 15/15

Now we have 12x/15 + 20/15 = 30x/15

With everything in the same denominator we can solve the new equation of
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20 = 18x

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3 years ago

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in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

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3 years ago

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aalyn [17]

combine your like terms and get x by its self

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3 years ago

The taxi driver charges $3.50 just to get in the cab and then $2.50 per mile. If Lisa travels m miles, which equation

Kryger [21]

Answer:r=2.5m+3.5

Step-by-step explanation:

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3 years ago

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