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2 years ago

The percent change from $10 to $27

1 answer:

4 0

→ $\frac{(27-10)}{|10|}$ × 100

→ $\frac{17}{10}$ × 100

→ 1.7 × 100 = 170

→ So, that means the change is → 170% ←

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Ugo [173]

The answer would be (F) 14

8 0

3 years ago

A study reported that the average age of menarche of girls entering the first year class of a small American private college in

Verizon [17]

Answer:

Null hypothesis: $\mu = 11.89$

Alternative hypothesis: $\mu \neq 11.89$

And we want to test this with a confidence interval:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

After conduct the interval of 95% for the true mean we got: (11.59, 13.31)

And for this case the confidence interval contains the value of 11.89, so then we have enough evidence to FAIL to reject the null hypothesis at 5% of significance that the true mean is 11.89.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=12.98$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n=30 represent the sample size

Solution to the problem

For this case we want to test the following hypothesis:

Null hypothesis: $\mu = 11.89$

Alternative hypothesis: $\mu \neq 11.89$

And we want to test this with a confidence interval:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

After conduct the interval of 95% for the true mean we got: (11.59, 13.31)

And for this case the confidence interval contains the value of 11.89, so then we have enough evidence to FAIL to reject the null hypothesis at 5% of significance that the true mean is 11.89.

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3 years ago

What is the point slope form of the line with slope 2/5 that passes through the point (-4,-7) ?

Korolek [52]

The point slope form of the line is:

D. y+4=2/5(x+7)

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2 years ago

Read 2 more answers

The volume of a cylinder is 4 pi x3 cubic units and its height is x units.

Rzqust [24]

Answer:

$2x$