Answer:
806 yd sq.
Step-by-step explanation:
Area=(length)(width), so to find the surface area you can just find the area of each side and then add then all together.
They already gave you the length of some of the sides, so you should use that to help you find the length of all the sides.
You can see the entire prism's length is 17 yd, width is 4 yd, and height is 14 yd.
The large visible side's area would be (14)(17)= 283 yd. There's another one of these side's on the other side that we can't see. So we would do (283)(2) = 566 yd sq.
Next, we'll find the area of the side on the side by doing (14)(4)=56. Once again, there's two of these sides so we do (56)(2) to get 112 yd sq for this side.
Finally, we'll find the area of the top side. We can do (4)(17) =68, and then (68)(2) to get 138 yd sq.
Now, we have the area of each side of the prism! To find the total surface area, just add them all together. 556+112+138=806.
The surface area would be 806 yd sq.
Answer:
$28
Step-by-step explanation:
First to solve this get the original amount before his parents gave him $6
20-6=14
So he had $14 after spending it at the batting cages.
It is stated he spent half of his money there so multiply 14 by 2
14 x 2=28
So he has a weekly allowance of $28
Right square pyramid V=189cm³
Answer:

Step-by-step explanation:
Given



Required
Determine the coordinates of P
The coordinate of a point when divided into ratio is:

Where



This gives:



