Can anyone do this?

Mathematics

2 answers:

elixir [45]4 years ago

8 0

The answer is Tuesday there will be 15 teachers for 179 students and 12 times 15 is 180

grandymaker [24]4 years ago

5 0

On Tuesday and Friday there would be enough teachers. To find this answer divide the number of kids by 12, and see if the answer is below the number of students.
Tuesday - 179/12=14.9 - there are 15 teachers - enough
Wednesday - 162/12=13.5 - there are 13 teachers - not enough
Thursday - 170/12=14.1 - there are 14 teachers - not enough
Friday - 143/12=11.8 - there are 12 teachers - enough

Hope I explained that good enough :)

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Given that (x+y+z)(xy+xz+yz)=18 and that x^2(y+z)+y^2(x+z)+z^2(x+y)=6 for real numbers x, y, and z, what is the value of xyz?

worty [1.4K]

Answer:

Step-by-step explanation:

$(x+y+z)(xy+xz+yz)=18$ Equation 1

$x^2(y+z)+y^2(x+z)+z^2(x+y)=6$ Equation 2

What is the value of $xyz$ where each variable represents a real number?

Let's expand equation 1:

$(x+y+z)(xy+xz+yz)=18$

$x(xy)+x(xz)+x(yz)+y(xy)+y(xz)+y(yz)+z(xy)+z(xz)+z(yz)=18$

Simplify each term if can:

$x^2y+x^2z+xyz+y^2x+xyz+y^2z+xyz+z^2x+z^2y=18$

See if we can factor a little to get some of the left hand side of equation 2:

The first two terms have $x^2$ and if I factored $x^2$ from first two terms I would have $x^2(y+z)$ which is the first term of left hand side of equation 2.