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3 years ago

10

To make an international telephone call you need the code for the country you are calling. The codes for country A country B and

C are three consecutive
integers whose sum is 93 find the code for each country

1 answer:

V125BC [204]3 years ago

3 0

Divide 93 by 3 to get 31. This is B and both A and C will be one number apart.
A is 30, B is 31, C is 32.

Hope this helps!

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Read 2 more answers

The average Act score follows a normal distribution, with a mean of 21.1 and a standard deviation of 5.1. What is the probabilit

ohaa [14]

Answer:

0.43% probability that the mean IQ score of 50 randomly selected people will be more than 23

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

$\mu = 21.1, \sigma = 5.1, n = 50, s = \frac{5.1}{\sqrt{50}} = 0.7212$

What is the probability that the mean IQ score of 50 randomly selected people will be more than 23

This is 1 subtracted by the pvalue of Z when X = 23. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{23 - 21.1}{0.7212}$

$Z = 2.63$

$Z = 2.63$ has a pvalue of 0.9957

1 - 0.9957 = 0.0043

0.43% probability that the mean IQ score of 50 randomly selected people will be more than 23

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3 years ago

How to solve it in quadratic functions

natita [175]

Answer:

x = 2

x = -3/2 or -1.5

Step-by-step explanation:

For this, I would use the "slip and slide" method. LOL I know the name is cheesy, but that's what my teacher called it!

First, you "slip" the coefficent of the leading term (2) to the constant, and multiply.

The equation becomes:

x² - x - 6(2) = 0

x² - x - 12 = 0

Then, you factor this out by looking at the second and third terms. You're looking for 2 factors of -12 that would add up to -1 ( the coefficent of the second term).

Automatically, think of 3 and 4, because the difference between them is 1.

The factors must be (x-4) and (x+3) because they multiple to -12, and add up to -1.

This step is extremely important! Lol I used to forget it a lot, but make sure you divide the constant in each factor by the original number you "slipped".

It would become (x-(4/2))(x+3/2) = (x-2)(x+3/2)

With (x+3/2), you don't want to leave it as a fraction or decimal. It's equivalent to (2x+3). However, the informal form is easier to identify the value of x.

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

α + β = 180°

∠BFE and ∠FBC

∠CEF and ∠BCE

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