Given
Rob is twice Joshua's age
Nick is 5 years older than Joshua.
sum of all their ages is 45.
Find the age of nick.
To proof
As given
Rob is twice Joshua's age
let Joshua's age = x
than Rob age = 2x
Nick is 5 years older than Joshua.
Nick age = 5 + x
sum of all their ages is 45
than the equation becomes
Joshua's age + Rob age + Nick age = 45
put the value
x + 2x + 5 + x = 45
4x = 40
x = 10
Joshua's age = 10 year
than Rob age = 20 year
Nick age = 5 + 10
= 15year
Hence proved
Answer:
x>5
Step-by-step explanation:
-3(2x+5)<-45
2x+5<-45/-3
2x+5<15
2x<15-5
2x<10
x<10/2
x<5
x>5
Answer:
f(x) = -4x² + 19x - 18
Step-by-step explanation:
i) If it is translated 2 units in the positive x direction, therefore we use f(x-2)
f(x) = 2x² - 9.5x + 6
If it is then translated 3 units in the positive y, we add 3 to the input function to get:
ii) stretched vertically by a factor of 2, we multiply the function by 2 to get:
iii) reflected across the x-axis
we multiply the parent function by –1, to get a reflection about the x-axis.
P(compact car) = number of compact cars / total number of cars = 4/25 = 16%
1. Find the slope
2. Y - Y1 = M ( X -X1) Plug the value. M is the slope and the point (X1,Y1)
