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timama [110]
3 years ago
8

Give four pairs of prime numbers whose difference is 2​

Mathematics
2 answers:
zubka84 [21]3 years ago
5 0

Answer:

(3, 1) (5, 3) (7, 5) (13, 11)

Step-by-step explanation:

photoshop1234 [79]3 years ago
4 0

There are only three of them that I know of:

(7, 5) (13, 11) (19,17)

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Option (C)

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In the given circle, AB is a chord passing through the center O.

Therefore,chord AB is a diameter of the circle and OC is the radius.

AO = OB = OC

OC⊥AB, and length of OC = 7 cm

By applying Pythagoras theorem in right ΔBOC,

BC² = OC² + OB²

BC = \sqrt{OC^{2}+OB^{2}}

     = \sqrt{7^2+7^2}

     = 7\sqrt{2}

     ≈ 9.9 units

Therefore, Option (C) will be the answer.  

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Need help ASAP with the correct answer
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