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2 years ago

What is the solution of y/-2 <- 5

Mathematics

1 answer:

makkiz [27]2 years ago

5 0

Answer:

Step-by-step explanation:

Y=-10

-5/2=-2.5

Keep in mind that...when dealing with negative numbers, the number closer to zero is the bigger number.

2.5 if closer to zero so the answer is F

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Work out the answers to the following:

salantis [7]

Step-by-step explanation:

a)9000

b)40

c)6300

d)125

I hope it's helpful!!

7 0

3 years ago

Please help quarter ends tomorrow and I don’t know what to do I’m failing all my classes

Nutka1998 [239]

Step-by-step explanation:

x = -10, y = 10

y= -4x+4

m1×m2 = -1

-4 × m2 = -1

m2 = 1/4

y-y1 = m(x-x1)

y-10 = 1/4(x+10)

y-10 = 1/4x +10/4

(×4)

4y-40=x+10

4y=x+50

x-4y+50=0

3 0

3 years ago

Subtract. Express your answer in lowest terms.

natima [27]

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7 0

3 years ago

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Ganezh [65]

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7 0

3 years ago

Read 2 more answers

A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.

scZoUnD [109]

Answer: The required ratio will be

$84:1034$

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

$2x=30\\\\x=\frac{30}{2}=15\ inches$

So, Length of AD becomes

$3x=3\times 15=45\ inches$

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

$\frac{30}{2}=15\ inches$

So, Area of semicircle along AB and CD is given by

$2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2$

Radius of semicircle along AD is given by

$\frac{45}{2}=22.5\ inches$

Area of semicircle along AD and BC is given by

$2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2$

And the combined area of the semicircles is given by

$\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2$

Area of rectangle is given by

$Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2$

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

$1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034$

Hence, the required ratio will be

$84:1034$

8 0

3 years ago