36% is the answer to the question
Answer:
The correct option is A. x – 1 < n < 3x + 5
Step-by-step explanation:
In a triangle sum of any two sides is always greater than the third side.
Now, the sides of the triangle are given to be :
2x + 2, x + 3 , n
Now, first take 2x + 2 and x + 3 as two sides and the side of length n as third side.
By using the property that sum of two sides is always greater than the third side in a triangle.
⇒ 2x + 2 + x + 3 > n
⇒ 3x + 5 > n ......(1)
Now, take n and x + 3 as two sides and the side of length 2x + 2 as the third side of triangle.
So, by the property, we have :
n + x + 3 > 2x + 2
⇒ n > x - 1 ...........(2)
From both the equations (1) and (2) , We get :
x – 1 < n < 3x + 5
Therefore, The correct option is A. x – 1 < n < 3x + 5
Answer:
Subtract from both sides of the equation the term you don't want
Step-by-step explanation:
In solving equations, you generally want to "undo" operations that are done to the variable. Addition is "undone" by adding the opposite (that is, subtracting the amount that was added). Multiplication is "undone" by division.
If you have variables on both sides of the equation, pick one of the variable terms and subtract it from both sides of the equation.
<u>Example</u>
2x = x +1
If we choose to subtract x, then we will have a variable term on the left and a constant term on the right:
2x -x = x -x +1 . . . . . . . x is subtracted from both sides
x = 1 . . . . . . simplify
__
Note that we purposely set up this example so that removing the variable term from the right side caused the variable term and constant term to be on opposite sides of the equal sign. It may not always be that way. As long as you remember that an unwanted term can be removed by subtracting it (from both sides of the equation), you can deal with constant terms and variable terms no matter where they appear.
_____
<em>Additional Comment</em>
It usually works well to choose the variable term with the smallest (or most negative) coefficient. That way, when you subtract it, you will be left with a variable term that has a positive coefficient.
Answer:
The ratio of her savings to expenditure <u>1 : 7</u>.
Step-by-step explanation:
Given:
Neelam's annual income is Rs. 288000.
Her annual savings amount to Rs. 36000.
Now, to get the ratio of her savings to her expenditure:
So, we get the expenditure first:
Expenditure = Income - Savings.
Expenditure = 288000 - 36000 = Rs. 252000.
Now, <em>the ratio of savings to expenditure:</em>
Thus, Savings:Expenditure = 1:7.
Therefore, the ratio of her savings to expenditure 1 : 7.
Answer:
We can find the sum of all the coefficients by substituting all the variables in the expansion with one.
a. u=1,v=1
sum=
=
b.u=1,v=1
sum=
=1
c.u=1,v=1
sum=
=-1
d.u=1,v=1
sum=
=-
e.i=1
sum=
=
f.i=1
sum=
=0
g.i=1
sum=
=
h.i=1
sum=
=
