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Nikitich [7]
2 years ago
15

Se va a colocar una escalera que mide 5 metros (m) de longitud sobre una pared. El fabricante de la escalera recomienda que, por

seguridad, el ángulo que forme la escalera con el piso sea de 78°, ¿Cuál será la distancia sobre el piso del pie de la escalera a la pared?
Mathematics
1 answer:
ivolga24 [154]2 years ago
7 0

Answer:

4.9 m

Step-by-step explanation:

Resolvemos la pregunta anterior usando la función trigonométrica de seno

sin θ = Opuesto / Hipotenusa

θ = 78 °

Hipotenusa = Longitud de la escalera = 5 m

Opuesto = Distancia sobre el suelo = x

sin 78 = x / 5m

Multiplicar cruzada

x = sin 78 × 5 m

x = 4.8907380037m

Aproximadamente

= 4.9 m

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Triangle ABC has the angle measures shown. Measure of angle A = (2 x) degrees. Measure of angle B = (5 x) degrees. Measure of an
Gnoma [55]

Answer:

<h3>             The true statement is the first:</h3><h2>         Measure of angle A = 20 degrees</h2>

Step-by-step explanation:

The sum of the measure of the interior angles in a triangle is 180°

m∠A + m∠B + m∠C = 180°

(2x)° + (5x)° + (11x)° = 180°

   (18x)° = 180°

       x = 10

A = (2×10)° = 20°     {<u>the first statement is true}</u>

B = (5×10)° = 50°      {the second statement is false}

C = (11×10)° = 110°

m∠A + m∠B = 20° + 50° = 70° ≠ 90°   {the third statement is false}

m∠A + m∠C = 20° + 110° = 130° ≠ 120°   {the fourth statement is false}

3 0
2 years ago
Read 2 more answers
PLEASE HELP!! URGANT!!
ella [17]

Answer: 100

set up equation: GHE+EHI=GHI

(x+38)+(x+104)=134

calculate

you get x= -4

put -4 into EHI

(-4)+104= 100

8 0
3 years ago
The product of two numbers is 161 , one of number is 7,find the other number. ​
Diano4ka-milaya [45]

let the other number be " n "

now, according to above condition :

  • n × 7 = 161

  • n = 161 ÷ 7

  • n = 23

therefore, the other number would be 23.

4 0
3 years ago
Here are the test scores for 10 students in Mr. P's class.
lutik1710 [3]
  • We need mean

\\ \rm\hookrightarrow Mean=\dfrac{Sum}{n}

\\ \rm\hookrightarrow \dfrac{59+94+57+87+75+90+82+57+65+77}{10}

\\ \rm\hookrightarrow 74.3\%

7 0
2 years ago
Help me with this... ​
marin [14]

i. 171

ii. 162

iii. 297

Solution,

n(U)= 630

n(I)= 333

n(T)= 168

i. Let n(I intersection T ) be X

333 - x + x + 468 - x = 630 \\ or \: 333 + 468 - x = 630 \\ or \: 801 - x = 630 \\ or \:  - x = 630 - 801 \\ or \:  - x =  - 171 \\ x = 171

<h3>ii.n(only I)= n(I) - n(I intersection T)</h3><h3> = 333 - 171</h3><h3> = 162</h3>

<h3>iii. n ( only T)= n( T) - n( I intersection T)</h3><h3> = 468 - 171</h3><h3> = 297</h3>

<h3>Venn- diagram is shown in the attached picture.</h3>

Hope this helps...

Good luck on your assignment...

4 0
3 years ago
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