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blondinia [14]
3 years ago
8

NEED HELP ASAP! I'll mark brainliest as well. Line l has the equation y=3x–4. Write the equation of the image of I after a dilat

ion with a scale factor of 2, centered at the origin. Write your answer in slope-intercept form.
y =
Mathematics
1 answer:
faust18 [17]3 years ago
8 0

Answer:

y=3x-8

Step-by-step explanation:

All you do is multiply the y-intercept which is -4 with the dilation of 2 which means multiply it by 2.

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How can you solve problems by ordering rational numbers from least to greatest?
Mariana [72]

Answer:

B same form

Step-by-step explanation:

By using them for fractions or decimals. You can compare fractions by having them from least to greatest and it helps in getting the same denominator for fractions.

6 0
2 years ago
Read 2 more answers
Can someone solve this please
grandymaker [24]

Answer:15. 5/8 = 0.625

Step-by-step explanation:

5 0
2 years ago
The sum of five consecutive multiples of 4 is 20.Find the smallest integer.
Aloiza [94]

Answer:

The smallest integer is -4.

Step-by-step explanation:

Let the smallest integer be x.

Since the integers are all multiples of 4, they are

=> x, x+4, x+8, x+12 and x+16

=> x + x+4 + x+8 + x+12 + x+16 = 20

=> 5x + 40 = 20

Subtract 40 from both sides of the equation

5x +40 - 40 = 20 - 40

5x = -20

Divide both sides by the coefficient of x(which is 5)

\frac{5x}{5} = \frac{-20}{5}

x = -4

∴ the smallest integer is -4.

Hope this helps!!!

6 0
2 years ago
F(1)=-12, f(n)=2f(n-1) <br> find first 4 terms
amid [387]
<h3>First four terms are:   -12, -24, -48, -96</h3>

============================================

Explanation:

The notation f(1) = -12 tells us that the first term is -12.

The equation f(n) = 2*f(n-1) indicates that we're multiplying the (n-1)th term by 2 to get the nth term. Basically we multiply each term by 2 to get the next term.

-12*2 = -24

-24*2 = -48

-48*2 = -96

So the first four terms are -12, -24, -48, -96.

-----------------------------------

Alternative Approach

f(1) = -12 .... first term

f(n) = 2*f(n-1) ... nth term recursive formula

f(2) = 2*f(2-1) ... plug in n = 2

f(2) = 2*f(1)

f(2) = 2*(-12) ... plug in f(1) = -12

f(2) = -24 ... second term

f(n) = 2*f(n-1) .... resetting for the next computation

f(3) = 2*f(3-1) ... plug in n = 3

f(3) = 2*f(2)

f(3) = 2*(-24)  ... plug in f(2) = -24

f(3) = -48 .... third term

f(n) = 2*f(n-1) ... one more reset

f(4) = 2*f(4-1) .... plug in n = 4

f(4) = 2*f(3)

f(4) = 2*(-48) ... plug in f(3) = -48

f(4) = -96 ... fourth term

We get the first four terms to be -12, -24, -48, -96, which was the same as earlier.

4 0
2 years ago
Algebra help please?
Alika [10]

Ok, basically if you want to find when both equations are equal just make them equal to each other. 0.925x^2 - 4x + 20  = -1.125x^2 + 6x + 40.

From there use algebraic steps to find out what x is ( the break - even point ).

0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40

0.855625x - 4x + 20 = 1.265625x + 6x + 40

-0.41x - 4x + 20 = 6x + 40

-4.41x + 20 = 6x + 40

20 = 10.41x + 40

-20 = 10.41x

-1.92122958694 = x

Rounded to the nearest tenth it's -1.9 = x.

Tell me if I got something wrong :)

3 0
3 years ago
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