Question

Write the equation in standard form of the circle whose diameter has endpoints of (-2, 4) and (8,-6).

Answer 1

Answer:

(x - 3)^2 + (y + 1)^2 = 50.

Step-by-step explanation:

The center of the circle is the midpoint of the diameter

= (-2+8)/2 , (4 - 6)/2

= (3, -1).

The radius^2  can be calculated from one point on the circle ( -2, 4) and the center (3, -1).

The radius^2 =  (-2-3)^2 + (4- -1)^2

= 25 + 25 = 50.

So the equation of the circle

is (x - a)^2 + (y - b)^ = r^2   where (a, b) is center and radius = r.

= (x - 3)^2 + (y + 1)^2 = 50