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3 years ago

Determine whether the equation is an identity or whether it has no solution. 2(a-3)=4a(2a-6)

Mathematics

2 answers:

vovikov84 [41]3 years ago

7 0

Answer:

Actually i think it does have a solution, if it does it would be a=1/4, 3

If i'm wrong i am very sorry..... So, if that not right then your answer is that it has no solution.....

Stay safe and have a Merry Christmas!!!!!!! :D

PSYCHO15rus [73]3 years ago

4 0

Answer:

It has no solution.

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Arielle wants to make a circular garden. She has enough fencing for a garden circumference of 15 feet. There is a 7-foot gap bet

lesantik [10]

Answer:

yes

Step-by-step explanation:

We need to check if the circle with a circumference of 15 feet is smaller then 7 feet. If so it possible.

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There fore d = 15/pi

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3 years ago

Item 15

Elenna [48]

Answer:

Step-by-step explanation:

i read though actually easy

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3 years ago

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Ksivusya [100]

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3 years ago

9) (0.03)(0.004) = A) 0.12 B) 0.012 C) 0.0012 D) 0.00012

Valentin [98]

Answer:

Step-by-step explanation:

You got the answer right it D

(0.03) multiplied by (0.004) is 0.00012

Multiply 3 by 4 and add all the zeros together

So 0.00012

4 0

3 years ago

Read 2 more answers

Can someone please help me with this again? 5-7 Thank you so much!

SIZIF [17.4K]

Hi there!

Use the property:

$\frac{x^a}{x^b} = x^{a - b}$
Now, solve by variable.

$\frac{x^2}{x} = x^{2 - 1} = x\\\\\frac{y^5}{y^4} = y^{5 - 4} = y$

Rewrite:
$= x * y * z^3 = \boxed{\text{ D. } xyz^3}}$

Solve the inside of the parenthesis, and each term separately.

Use the property:
$x^0 = 1$

$(7 + 3^2)^0 = 1 \\\\(8^0 + 3)^2 = (1 + 3)^2 = 4^2 = 16\\\\1 + 16 = \boxed{ \text{ C. } 17}$

Solve like above:
$(4 + 2^2)^0 = 1\\\\(7^0 + 4)^{-3} = (1 + 4)^{-3} = 5^{-3}$

The negative exponent indicates taking the reciprocal. Using the property:
$x^{-a} = \frac{1}{x^a}$

Therefore:
$5^{-3} = \frac{1}{5^3} = \boxed{ \text{ D. }\frac{1}{125}}$

4 0

2 years ago

Determine whether the equation is an identity or whether it has no solution. 2(a-3)=4a(2a-6)​

Determine whether the equation is an identity or whether it has no solution. 2(a-3)=4a(2a-6)