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murzikaleks [220]
3 years ago
10

Determine whether the equation is an identity or whether it has no solution. 2(a-3)=4a(2a-6)​

Mathematics
2 answers:
vovikov84 [41]3 years ago
7 0

Answer:

Actually i think it does have a solution, if it does it would be a=1/4, 3

If i'm wrong i am very sorry..... So, if that not right then your answer is that it has no solution.....

Stay safe and have a Merry Christmas!!!!!!! :D

PSYCHO15rus [73]3 years ago
4 0

Answer:

It has no solution.

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The graph of y=f(x) is above. If f(−4)=k, what is the value of f(k)?
cupoosta [38]

Answer:

B

The answer is B, which is -1.5.

3 0
3 years ago
Round 34.037 to 3 significant figures. <br>a. 34.04 <br>b. 34 <br> c. 34.037 <br> d. 34.0​
dezoksy [38]

Answer:

My answer to the question is 34.0

6 0
3 years ago
Please help work this out
BigorU [14]

Answer:

Area=190.091 cm^2

Step-by-step explanation:

Area = 1/2(Pi x r^2)    one-half because it's a semi-circle

Area=1/2(3.14 x 11^2)

11^2=121 so, Area=1/2(3.14 x 121)

Area=1/2(379.94)

Area=189.97 cm^2

adjustment:

Area=1/2(3.142 x 11^2)

Area=1/2(3.142 x 121)

Area=1/2(380.182)

Area=190.091

5 0
3 years ago
Write an equation of the line that passes through the given points.<br> (-1,7) and (4, -8)
djverab [1.8K]

Answer:

y=-3x+4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-8-7)/(4-(-1))

m=-15/(4+1)

m=-15/5

m=-3

y-y1=m(x-x1)

y-7=-3(x-(-1))

y-7=-3(x+1)

y=-3x-3+7

y=-3x+4

3 0
3 years ago
Triangle ABC has vertices at A(3, 8) , B(11, 8) , and C(9, 12) . Triangle FGH has vertices at F(1, 3) , G(9, 3) , and H(7, 7) .
Alex17521 [72]
Hmm, (x,y)
x is horizontal or left right
y is vertical or up down


so

we see that A to F is move left 2 and down 5
B to G is left 2 and down 5
C to H is left 2 and down 5


so translatete ABC left 2 and down 5 and
translate FGH right 2 and up 5

not 1st option
2nd works
3rd works
4th is false


2nd and 3rd
6 0
3 years ago
Read 2 more answers
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