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liq [111]
3 years ago
6

A company advertises two car tire models. The number of thousands of miles that the standard model tires last has a mean \mu_S =

60μ S ​ =60 and standard deviation \sigma_S = 5σ S ​ =5. The number of miles that the extended life tires last has a mean \mu_E = 70μ E ​ =70 and standard deviation \sigma_E = 7σ E ​ =7. If mileages for both tires follow a normal distribution, what is the probability that a randomly selected standard model tire will get more mileage than a randomly selected extended life tire?
Mathematics
1 answer:
Andrew [12]3 years ago
5 0

Answer:

0.123

Step-by-step explanation:

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mafiozo [28]

Answer:There are two right triangles. You need to find the opposite side (the height) of each of them. The difference between the two is the height of the blade, x.

You know the adjacent, 440, and you are looking for the opposite, so you need to use tan for both.

tan (30) = y / 440

y = 440 * tan (30) = 254.034...

tan (38.8) = z / 440

y = 440 * tan (38.8) = 353.769.--

353.8 - 254.0 = 99.8 = 100 feet.

Step-by-step explanation:

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1 year ago
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2 years ago
ASAP PLS! What is 2k^2+3k-13=k^2+15?
shepuryov [24]

2k^2+3k-13=k^2+15

subtract k^2 -15 from each side

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3 years ago
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Question 1 of 10 Jerry drew AJKL and AMNP so that K = ZN, ZLE ZP, JK = 6, and MN = 18. Are AJKL and AMNP similar? If so, identif
butalik [34]

Answer:

This is the answer I got

Step-by-step explanation:

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though the two corresponding sides of the triangles mentioned are proportional (proportionality being 1:3 ) but they need not be similar

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