If <em>a</em> is fixed and <em>b</em>,<em>c</em> are unknowns then the equation <em>b</em>+<em>c</em>=10-<em>a</em> has 11-<em>a</em> solutions. They are pairs (b,c): (0,10-a), (1,9-a), (2,8-a), ... (10-a,0). As <em>a</em> runs from 0 to 10 we have total number of solutions (11-0)+(11-1)+...(11-1)=11+10+...+1=(1+11)*11/2=66.
Answer:
(-3, 5) is C
(0,-2) is D
(-2, -2) is E
Step-by-step explanation:
I’m assuming the numbers are 2/3 and 3/4 so find the common denominator. 2/3x4=8/12 and 3/4x3=9/12 so 8/12+9/12= 17/12 or 1 and 5/12
Answer:
it would be in the fourth quadrant, directly underneath where it is now. the base would be c and d
Answer:
i want to see the choices
