23 clothespins are placed on a clothesline at 2-foot intervals. How far is it from the first clothespin to the last one

After arianna completed some work, she figured she still had 78 21/100 pictures to paint. if she completed another 34 23/25 pict

dezoksy [38]

Subtract the number she completed from what she had left to paint originally.

The fractions have different denominators so first step is to rewrite the fractions with a common denominator.

23/25 can be rewritten as 92/100

Now you have 78 21/100 - 34 92/100

Because 21/100 is smaller than 92/100 subtract 1 whole number from 78 and rewrite 1 as 100/100 and add that to the fraction.

78 21/100 becomes 77 121/100

Now subtract :

77 121/100 - 34 92/100

77-34 = 43

And 121/100 - 92/100 = 29/100

Combine to get 43 and 29/100

3 0

3 years ago

in 2005, the total waste generated in a certain country was 3.474x10^9 pounds. also in 2005, the countrys population was 1.23x10

Serggg [28]

Answer:

2824

Step-by-step explanation:

Take the number of pounds and divide by the number of people:

3.474×10⁹ / 1.23×10⁶

Divide the coefficients and subtract the exponents:

(3.474 / 1.23) × 10⁹⁻⁶

2.824×10³

So the country produced about 2,824 pounds of garbage per person in 2005.

7 0

2 years ago

PLEASE HELP ME WITH THIS, I WILL DO ANYTHING!!!

vitfil [10]

Mean is the "meanest" because it requires the most work. Add up the values in your data set and divide by the number of terms in the data.

Let x represent attendees at Harry's Hoedown, then

Mean = $\frac{Martha's (M) + Shirly's (S) + Harry's (x) }{3}$

41 = $\frac{48 + 33 + x}{3}$

123 = 48 + 33 + x

123 = 81 + x

42 = x

Answer: 42

5 0

2 years ago

2x^2+3x-2, a=0 How do I find the derivative?

Ghella [55]

You can use the definition:

$\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h$

Then if

$f(x) = 2x^2+3x-2$

we have

$f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2$

Then the derivative is

$\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}$

I'm guessing the second part of the question asks you to find the tangent line to f(x) at the point a = 0. The slope of the tangent line to this point is

$f'(0) = 4(0) + 3 = 3$

and when a = 0, we have f(a) = f (0) = -2, so the graph of f(x) passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

y - (-2) = 3 (x - 0)

y + 2 = 3x

y = 3x - 2

5 0

3 years ago

Please help omg I don’t understand

In-s [12.5K]

The answer will be c

5 0

2 years ago