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ValentinkaMS [17]

2 years ago

7

9. John bought a used truck for $4,500. He made an agreement with the dealer to put $1,500 down and make payments of $350 for th

e next 10 months. The extra cost paid by taking this deal is equivalent to what actual yearly rate of interest?

1 answer:

kirza4 [7]2 years ago

6 0

Answer:

11.111111111111111...%

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What is the vertex of this parabola? y= 2x² + 4x +5

uranmaximum [27]

Answer:

vertex = (- 1, 3 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

$x_{vertex}$ = - $\frac{b}{2a}$

y = 2x² + 4x + 5 ← is in standard form

with a = 2, b = 4, then

$x_{vertex}$ = - $\frac{4}{4}$ = - 1

Substitute x = - 1 into the equation for corresponding value of y, that is

y = 2(- 1)² + 4(- 1) + 5 = 2 - 4 + 5 = 3

vertex = (- 1, 3 )

6 0

3 years ago

Prove that sinxtanx=1/cosx - cosx

maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

$\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}$

Taking the RHS, note

$\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}$

Remember that

$\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)$

Therefore,

$\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}$

Once

$\dfrac{\sin(x)}{\cos(x)} = \tan(x)$

Then,

$\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)$

Hence, it is proved

5 0

2 years ago

Thrice a number decreased by 5 exceeds twice the number by a unit find the number

viktelen [127]

Working attached below. Hope this helps! Any questions let me know :)

6 0

2 years ago

W÷5=? "With work if needed"

Svetach [21]

Answer: This question doesn't have an answer.

Step-by-step explanation:

8 0

2 years ago

Someone pls answer this it’s so confusing lol

GenaCL600 [577]

Answer:

<h2> $y = \frac{w}{h - {2c}^{3} }$ </h2>

Step-by-step explanation:

w = yh - 2yc³

First of all factorize y out of the expression on the right side of the equation

That's

w = y( h - 2c³)

Next divide both sides by (h - 2c³) to make y stand alone

We have

<h3> $\frac{y(h - {2c}^{3}) }{h - {2c}^{3} } = \frac{w}{h - {2c}^{3} }$ </h3>

We have the final answer as

<h3> $y = \frac{w}{h - {2c}^{3} }$ </h3>

Hope this helps you

4 0

3 years ago