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tensa zangetsu [6.8K]
3 years ago
8

URGENT HELP NEEDED!!!

Mathematics
1 answer:
lions [1.4K]3 years ago
6 0

Answer:

(a+b)^{2}- \sqrt[3]{x . 3y}

Step-by-step explanation:

<em>Subtract the cube root of the product of x and 3y from the square of the sum of a and b.  </em>

<em>A = The square of the sum of a and b is  </em>(a+b)^{2}

<em>B = The cube root of the product of x and 3y is  </em>\sqrt[3]{x . 3y}

<em>They want us to subtract B from A so B - A, therefore the following.</em>

(a+b)^{2}- \sqrt[3]{x . 3y}  

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zheka24 [161]

Answer:

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Step-by-step explanation:

In ΔABC and ΔCED,

AB║DE and AD is a transversal line,

m∠ABC = m∠CED [Alternate interior angles]

m∠ACB = m∠DCE [Vertically opposite angles]

ΔABC ~ ΔCED [By AA property of similarity]

Therefore, by the property of similar triangles, corresponding sides will be proportional.

\frac{AB}{DE}= \frac{AC}{DC}

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CD = 6

Since, AD = AC + CD

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3 years ago
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4 years ago
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