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tensa zangetsu [6.8K]
3 years ago
8

URGENT HELP NEEDED!!!

Mathematics
1 answer:
lions [1.4K]3 years ago
6 0

Answer:

(a+b)^{2}- \sqrt[3]{x . 3y}

Step-by-step explanation:

<em>Subtract the cube root of the product of x and 3y from the square of the sum of a and b.  </em>

<em>A = The square of the sum of a and b is  </em>(a+b)^{2}

<em>B = The cube root of the product of x and 3y is  </em>\sqrt[3]{x . 3y}

<em>They want us to subtract B from A so B - A, therefore the following.</em>

(a+b)^{2}- \sqrt[3]{x . 3y}  

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Given the arithmetic sequence an = 4 − 3(n − 1), what is the domain for n? All integers where n ≥ 1 All integers where n &gt; 1
krok68 [10]

All integers where n ≥ 1.

We have given that the sequence,

a_{n} =4-3(n-1)

We have to find the domain for n.

<h3>What is the meaning of arithmetic sequence?</h3>

Arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. Difference here means the second minus the first.

That is, a_{n} =a+(n-1)d

where a = first term of sequence.

d =common difference.

n =number of terms which belongs to natural numbers

By  the definition of arithmetic sequence n starts with 1

Remember that,the natural number starts with 1

Now, in given sequence  for nth term

a_{n} =4-3(n-1)

The domain for n is All integers where n ≥ 1.

To learn more about the arithmetic sequence visit:

brainly.com/question/20118982

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Step-by-step explanation:

when something like (1,6) is written consider it as (x,y). in this case, 1 is considered as x, and 6 is considered as y. if you substitute these number for x and x and y, (x =1 and y =6), you'll see that the equation will go from y=x +7, to 6=1+7. Which is not true.

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Step-by-step explanation:

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