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2 years ago

ITS DUE TODAY I NEED ANSWERS PLZZZ

Mathematics

1 answer:

kirza4 [7]2 years ago

4 0

Answer:

Step-by-step explanation:

1) = 132°

2) = 119°

3) = 47°

4)12x - 6 = 2+11x

x = 8

5) 19x + 5 = 100

19x = 95

x = 5

6) 7x = 8x - 11

11 = x

7) 2 + 8x = 9x - 4

6 = x

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Compute the perimeter of the figure given below. All angles are right angles.

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Find the missing side lengths. Leave your answers as radicals in simplest form. Please help!! Due today

Nataly_w [17]

Answer:

$m = 10\sqrt 3$

$n = 10$

Step-by-step explanation:

Required

Find m and n

Considering the given angle, we have:

$\sin(60) = \frac{Opposite}{Hypotenuse}$

This gives:

$\sin(60) = \frac{m}{20}$

Make m ths subject

$m = 20 * \sin(60)$

$\sin(60) =\frac{\sqrt 3}{2}$

So, we have:

$m = 20 *\frac{\sqrt 3}{2}$

$m = 10\sqrt 3$

Considering the given angle again, we have:

$\cos(60) = \frac{Adjacent}{Hypotenuse}$

This gives:

$\cos(60) = \frac{n}{20}$

Make n the subject

$n = 20 * \cos(60)$

$\sin(60) =\frac{1}{2}$

So, we have:

$n = 20 *\frac{1}{2}$

$n = 10$

5 0

2 years ago

Hey can you help me answer this question by giving me the answer?

Leto [7]

The value of f(a)=4-2a+6 $a^{2}$ , f(a+h) is $6a^{2} +6h^{2} -2a-2h+12ah$ , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6 $x^{2}$ .

Given a function f(x)=4-2x+6 $x^{2}$ .

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6 $a^{2}$ (By just putting x=a).

f(a+h)== $4-2(a+h)+6(a+h)^{2}$

=4-2a-2h+6( $a^{2} +h^{2} +2ah$ )

=4-2a-2h+6 $a^{2} +6h^{2} +12ah$

= $6a^{2} +6h^{2}-2a-2h+12ah$

[f(a+h)-f(a)]/h=[ $6a^{2} +6h^{2}-2a-2h+12ah$ -(4-2a+6 $a^{2}$ )]/h

= $(6a^{2} +6h^{2} -2a-2h+12ah)/h$

= $(6h^{2} -2h+12ah)/h$

=6h+12a-2.

Hence the value of function f(a)=4-2a+6 $a^{2}$ , f(a+h) is $6a^{2} +6h^{2} -2a-2h+12ah$ , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6 $x^{2}$ .

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2 years ago

Whic

andreyandreev [35.5K]

Figure A which has two rays connected at a vertex is an angle in this scenario.

<h3>What is an Angle?</h3>

This is formed when two rays share a common endpoint with there being different types of angles.

The common endpoint shared forms a vertex which is why Figure A was chosen as the most appropriate choice.

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1 year ago

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olganol [36]

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B) The coefficients are 7.5 and -9. FALSE. The coefficients are 7.5, -1/9 and 2. 50, being a constant, could be regarded as a coefficient in this case.

C) The variables are x and y. FALSE. There are three variables: x, y and z.

D) The like terms are 7.5y and 2y. TRUE. The variable (y) is the same in each term.

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