Question

Find the missing side lengths. Leave your answers as radicals in simplest form. Please help!! Due today

Answer 1

Answer:

$m = 10\sqrt 3$

$n = 10$

Step-by-step explanation:

Required

Find m and n

Considering the given angle, we have:

$\sin(60) = \frac{Opposite}{Hypotenuse}$

This gives:

$\sin(60) = \frac{m}{20}$

Make m ths subject

$m = 20 * \sin(60)$

$\sin(60) =\frac{\sqrt 3}{2}$

So, we have:

$m = 20 *\frac{\sqrt 3}{2}$

$m = 10\sqrt 3$

Considering the given angle again, we have:

$\cos(60) = \frac{Adjacent}{Hypotenuse}$

This gives:

$\cos(60) = \frac{n}{20}$

Make n the subject

$n = 20 * \cos(60)$

$\sin(60) =\frac{1}{2}$

So, we have:

$n = 20 *\frac{1}{2}$

$n = 10$