Answer:
Replace /* Your solution goes here */ with the following lines of code
for(i = 0;i<SCORES_SIZE-1;i++)
{
bonusScores[i]+=bonusScores[i+1];
}
Explanation:
The above iteration starts from the index element (element at 0) and stops at the second to the last element (last - 1).
Using an iterative variable, i
It adds the current element (element at i) with the next element; element at i + 1.
The full code becomes
#include<iostream>
using namespace std;
int main(void) {
const int SCORES_SIZE = 4;
int bonusScores[SCORES_SIZE];
int i = 0;
bonusScores[0] = 10;
bonusScores[1] = 20;
bonusScores[2] = 30;
bonusScores[3] = 40;
for(i = 0;i<SCORES_SIZE-1;i++)
{
bonusScores[i]+=bonusScores[i+1];
}
/* Your solution goes here */
for (i = 0; i < SCORES_SIZE; ++i) {
printf("%d ", bonusScores[i]);
}
printf("\n");
return 0;
}
See attachment for .cpp file
Solution :
Public Function Is a Leap_Year(Year As_Integer) As Integer
'Dim Tor_F for local variable declaring if value is t/f.
Dim TorF As For Boolean
'Pre conditions: Year > 1581 and Year < 3000
If Year > 1581 And Year <> 1700 Or 1800 Or 1900 Then
IsLeapYear = Year / 4
Else
IsLeapYear = False
TorF = False
End If
End Function
Answer:
The answer to this question is Live Online Courses.
Explanation:
When we are enrolled in an online learning courses that is live so we can observe that there is synchronous communication in training.
The instructor is teaching at some other end using live broadcasting or other video broadcasting methods via internet and we are at the receiving end.
Answer:
The answer is database to organize date.
Explanation: