restart.is done after the computer is passed through configuration
Using a linear search to find a value that is stored in the last element of an array of 20,000 elements, 20,000 element(s) must be compared.
Answer:
For this wild card mask 0.0.15.255 the ACE IP address will be 172.16.47.254
Explanation:
ACL is the access control list that is used to enlist the ip addresses that allowed or restricted to access the network. ACE is an IP address from the list ACL that has all rules and regulations related to access of network. The ACE could be in the range of IP address in ACL. ACL can be calculated with the help of initial IP address adding with wild card mask.
So
Initial IP address is = 172.16.32.0
Wild card mask =0.0.15.255
by adding above values we can find the last IP address of ACL.
after addition
Final IP address is = 172.16.47.255
The options that are available with question, Only option between the range is 172.16.47.254. So we can say that This is the only ACE IP address in options.
Answer:
I think in there transmission you know inputs into ports like for their own
Explanation:
likeslike Spanish and is obviously inputs and outputs their portsinto the portsdifferent ports you know
The simulation, player 2 will always play according to the same strategy.
Method getPlayer2Move below is completed by assigning the correct value to result to be returned.
Explanation:
- You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.
#include <bits/stdc++.h>
using namespace std;
bool getplayer2move(int x, int y, int n)
{
int dp[n + 1];
dp[0] = false;
dp[1] = true;
for (int i = 2; i <= n; i++) {
if (i - 1 >= 0 and !dp[i - 1])
dp[i] = true;
else if (i - x >= 0 and !dp[i - x])
dp[i] = true;
else if (i - y >= 0 and !dp[i - y])
dp[i] = true;
else
dp[i] = false;
}
return dp[n];
}
int main()
{
int x = 3, y = 4, n = 5;
if (findWinner(x, y, n))
cout << 'A';
else
cout << 'B';
return 0;
}