Question

A wire 48 m long carries a current of 18 A from west to east.

Answer 1

Step-by-step explanation:

Given that,

The length of a wire, L = 48 m

Current in the wire, I = 18 A (west to east)

The magnetic field in the wire, B = $8.3\times 10^4\ T$ (towards south)

The magnetic force acting on the wire is given by :

$F=I(L\times B)\\\\F=48\cdot18\cdot8.3\cdot10^{-4}\ N\\\\F=0.71\ N$

Using right hand rule, the direction of magnetic force is upwards.