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2 years ago

A wire 48 m long carries a current of 18 A from west to east.

Mathematics

1 answer:

Arisa [49]2 years ago

4 0

Step-by-step explanation:

Given that,

The length of a wire, L = 48 m

Current in the wire, I = 18 A (west to east)

The magnetic field in the wire, B = $8.3\times 10^4\ T$ (towards south)

The magnetic force acting on the wire is given by :

$F=I(L\times B)\\\\F=48\cdot18\cdot8.3\cdot10^{-4}\ N\\\\F=0.71\ N$

Using right hand rule, the direction of magnetic force is upwards.

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Katarina [22]

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3 years ago

What is a solution to the system? y = x^2 + 2x - 15 y – 4x = -12

astra-53 [7]

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Answer:

(x, y) = (-1, -16) or (3, 0)

Step-by-step explanation:

Perhaps you want to solve the system of equations ...

y = x^2 +2x -15
y -4x = -12

Substituting the first expression for y into the second equation gives ...

x^2 +2x -15 -4x = -12

x^2 -2x -3 = 0 . . . . . . . . add 12

(x -3)(x +1) = 0 . . . . . . . factor

Solutions are the values of x that make the factors zero: x = 3, x = -1.

The corresponding values of y are ...

y = -12 +4x

y = -12 +4{-1, 3} = -12 +{-4, 12} = {-16, 0}

The solutions to the system are ...

(x, y) = (-1, -16) or (3, 0)

5 0

2 years ago

Divers in a competition are scored by an international panel of judges. The highest and the lowest scores are dropped. The total

Fudgin [204]

From the statements given in the problem, we can say that:

Final Score = (total of the remaining scores) * degree of difficulty * 0.6

Therefore:

97.2 = (total of the remaining scores) * 4.0 * 0.6

total of the remaining scores = 40.5

Therefore the judges could have scored which has a total of 40.5

6 0

3 years ago

Read 2 more answers

Please help will mark Brainliest!!

seraphim [82]

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2 years ago

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yanalaym [24]

Answer:

$\frac{f(x+h)-f(x)}{h}$ $=2x + h$

Step-by-step explanation:

Given

$f(x)= x^2 + 2$

Required

Determine: $\frac{f(x+h)-f(x)}{h}$

First, we calculate f(x + h)

$f(x)= x^2 + 2$

$f(x+h) = (x+h)^2+2$

$f(x+h) = x^2+2xh+h^2+2$

So, we have:

$\frac{f(x+h)-f(x)}{h}$ $= \frac{x^2 + 2xh + h^2 + 2 - x^2 - 2}{h}$

$\frac{f(x+h)-f(x)}{h}$ $= \frac{x^2 - x^2+ 2xh + h^2 + 2 - 2}{h}$

$\frac{f(x+h)-f(x)}{h}$ $= \frac{2xh + h^2}{h}$

$\frac{f(x+h)-f(x)}{h}$ $=2x + h$

8 0

2 years ago