Which method can be used to solve - 3-5 = 15? PLEASE HELP!
2 answers:
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-x+3y+3=0 <-- This puts the expression into an equation to make it solvable.
3y+3=x <-- Use Addition Property of Exponents to move the (x) to the right
3y=x-3 <-- Use Subtraction Property of Exponents to move the (3) to the right
y=
-1 <-- Use Division Property of Exponents to remove the 3 from y
y=-1 < This is the equation for the y-intercept
-x+3y+3=0 <-- Same as above, makes it so the expression is an equation to solve
-x+3=-3y <-- Use Subtraction Property of Exponents to move the 3y to the right
-x=-3y-3 <-- Use Subtraction Property of Exponents to move the 3 to the right
x=3y+3 <--Use Divison Property of Exponents to remove the -1 from x
x=3y+3 <-- This is the equation for the x-intercept
Hope this helped!
3y+3=x <-- Use Addition Property of Exponents to move the (x) to the right
3y=x-3 <-- Use Subtraction Property of Exponents to move the (3) to the right
y=
y=
-x+3y+3=0 <-- Same as above, makes it so the expression is an equation to solve
-x+3=-3y <-- Use Subtraction Property of Exponents to move the 3y to the right
-x=-3y-3 <-- Use Subtraction Property of Exponents to move the 3 to the right
x=3y+3 <--Use Divison Property of Exponents to remove the -1 from x
x=3y+3 <-- This is the equation for the x-intercept
Hope this helped!
If X and Y are Boolean variables, then X + Y represents disjunction (OR) and XY represents conjunction (AND), and X' denotes the negation (NOT). So X + Y = 1 if either X = 1 or Y = 1, and XY = 1 only if both X = 1 or Y = 1.
Now,
(X + Y) (X + Y') = XX + YX + XY' + YY'
… = X + X (Y + Y') + 0
… = X + X
… = X
or in table form,