yes, if a point is on the bisector of an angle, then the point is outdistance
from sides of the angle
To find is out put it like this 2 8
5 x
you multiple so 2 times what eduals 8 then you take that and multiply by 5
Given:
The height of a golf ball is represented by the equation:

To find:
The maximum height of of Anna's golf ball.
Solution:
We have,

Differentiate with respect to x.


For critical values,
.




Differentiate y' with respect to x.


Since double derivative is negative, the function is maximum at
.
Substitute
in the given equation to get the maximum height.




Therefore, the maximum height of of Anna's golf ball is 6.25 units.
Answer:
∠AEC = 139°
Step-by-step explanation:
Since EC bisects ∠BED then ∠BEC = ∠CED = 4x + 1
∠AED = ∠AEB + ∠BEC + ∠CED = 180 ← straight angle
Substitute values into the equation
11x - 12 + 4x + 1 + 4x + 1 = 180, that is
19x - 10 = 180 ( add 10 to both sides )
19x = 190 ( divide both sides by 19 )
x = 10
Hence
∠AEC = ∠AEB + ∠BEC = 11x - 12 + 4x + 1 = 15x - 11, hence
∠AEC = (15 × 10) - 11 = 150 - 11 = 139°