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Kryger [21]
3 years ago
10

I need help with question 18. The answer is53√3 ft^2. But how do I get there?

Mathematics
2 answers:
Ghella [55]3 years ago
8 0

Answer:

52√3 ft²

Step-by-step explanation:

sin 60° = (√3) / 2 = h/8

h = 8 x (√3) / 2 = 4√3

cos 60° = 1/2 = a/8

a = 4         b = 15-4 = 11

area = left triangle + right rectangle

area = (4*4√3) / 2 + 11*4√3

        = 8√3 + 44√3

        = 52√3

sergij07 [2.7K]3 years ago
5 0

Answer:

Hope it helps....

Step-by-step explanation:

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find the area and circumference of the circule .(round your number to the nearest hunderth.) r=4.5 cm​
balu736 [363]

Answer:

28.2743338823

Step-by-step explanation:

The circumference of every circle is 3.14, and in order to find the area you must do Pi (3.14) times the radius doubled (\pix R2) Hope that helped!

4 0
2 years ago
what is the least number that must be added to 2000 so that the sum is divisible exactly 10,12,16and 18 ? do it step by step
Rudiy27

The integers divisible by any set of positive integers are the multiples of their LCM

let us first write the factored form of each

10 = 2×5

12 = 2×2×3

16 = 2×2×2×2

18 = 2 x3×3

Now we will find lcm of these numbers

LCM = 2×2×2×2×3×3×5 = 720

The multiples of 720 are divisible by 10,12,16 and 18.

2000/720 = 2.777777...

The least integer greater than that is 3, so 3×720 = 2160 is the least integer greater than 2000 that is divisible by 10,12,16 and 18.

so if we need to find what must be added to 2000 so that the sum is divisible by 10,12,16 and 18, we must subtract 2000 from 2160

2160-2000=160

so we must add 160 to 2000 so that the sum is divisible exactly 10,12,16and 18

5 0
3 years ago
4) The path of a satellite orbiting the earth causes it to pass directly over two
Naily [24]

Answers:

  • Satellite is approximately <u>2446.43 km</u> from station A.
  • Satellite is approximately <u>2441.61 km</u> above the ground.

=========================================================

Explanation:

I'm assuming tracking stations A and B are at the same elevation and are on flat ground. In reality, this is likely not the case; however, for the sake of simplicity, we'll assume this is the case.

The diagram is shown below. Points A and B describe the two stations, while point C is the satellite's location. Point D is on the ground directly below the satellite. We have these lengths

  • AB = 60 km
  • AD = x
  • CD = h

Focusing on triangle ACD, we can apply the tangent rule to isolate h.

tan(angle) = opposite/adjacent

tan(A) = CD/AD

tan(86.4) = h/x

x*tan(86.4) = h

h = x*tan(86.4)

We'll use this later in the substitution below.

--------------------

Now move onto triangle BCD. For the reference angle B = 85, we can use the tangent rule to say

tan(angle) = opposite/adjacent

tan(B) = CD/DB

tan(B) = CD/(DA+AB)

tan(85) = h/(x+60)

tan(85)*(x+60) = h

tan(85)*(x+60) = x*tan(86.4) .............  apply substitution; isolate x

x*tan(85)+60*tan(85) = x*tan(86.4)

60*tan(85) = x*tan(86.4)-x*tan(85)

60*tan(85) = x*(tan(86.4)-tan(85))

x*(tan(86.4)-tan(85)) = 60*tan(85)

x = 60*tan(85)/(tan(86.4)-tan(85))

x = 153.612786190499

--------------------

We'll use this approximate x value to find h

h = x*tan(86.4)

h = 153.612786190499*tan(86.4)

h = 2441.60531869599

h = 2441.61 km  is how high the satellite is above the ground.

Return to triangle ACD. We'll use the cosine rule to determine the length of the hypotenuse AC

cos(angle) = adjacent/hypotenuse

cos(A) = AD/AC

cos(86.4) = x/AC

cos(86.4) = 153.612786190499/AC

AC*cos(86.4) = 153.612786190499

AC = 153.612786190499/cos(86.4)

AC = 2446.43279498247

AC = 2446.43 km is the distance from the satellite to station A.

6 0
3 years ago
Lea walked 1/2 mile in 1/3 hour. How long will it take lea to walk 2 1/4 miles ?
cluponka [151]

takes her 20 minutes to walk 1/2 a mile  

2 miles=80 minutes  

1/4= 10 minutes i think  

so 80+10=1 1/2

{This is not my work!!!}

5 0
3 years ago
Read 2 more answers
How to divide 4 and 3,468 using long division
barxatty [35]

Answer:

i never understud it

Step-by-step explanation:

4 0
2 years ago
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