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3 years ago

a cell phone and phone case cost 110$ in total. the cell phone costs 100$ more than the phone case. How much was the cell phone?

Mathematics

2 answers:

telo118 [61]3 years ago

6 0

Answer:

$100

Step-by-step explanation:

We know that the total cost was $110 and that the phone is $100 more than the case. With this, we can figure out how much the case is, and use that information to find the price of the phone.

Case price = total price - 100

= 110 - 100

Case price = 10

Now that we know that the case price is $10, we can figure out the phone's price.

Phone price = total price - case price

= 110 - 10

= 100

The phone costs $100

Flauer [41]3 years ago

3 0

Answer:

210$ i hope this helped!

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3 years ago

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11 and 13 ONLY

gulaghasi [49]

11. The sum S of the first n consecutive positive integers, 1, 2, 3, ... , n, is given by the formula S=0.5n(n+1). Find n when S=120 and check your answer by addition.

$120 = \frac 1 2 n (n+1)$

$240 = n^2 + n$

$n^2 + n -240 = 0$

We need two numbers whose sum is 1 and multiply to -240, so two numbers whose difference is 1 and multiply to 240, 15 and 16. We factor:

$(n+16)(n-15)= 0$

$n=-16 \textrm{ or } n=15$

We reject the negative root.

n=15

Check:

1+2+3+4+5+6+7+8+9+10+11+12+13+14+15

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Let v be the speed of the boat in still water.

The speed downstream is v+4 so the time to travel 36 miles downstream is 36/(v+4)

The speed upstream is v-4 so the time to travel 36 miles upstream is 36/(v-4)

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3/4 = 36/(v-4) - 36/(v+4)

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