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2 years ago

HELPPPPPPP MULITPLY AND FIND OUT IF ALL HESE ARE CORRECT IF THEY'RE NOT TELL ME AND PLS GIVE ME THE ANSWERS FOR QUESTION 4

Mathematics

2 answers:

pashok25 [27]2 years ago

7 0

Answer:

Ok so the first one is right and the second one is right for the first question

For the second Question your also right

Step-by-step explanation:

Question 3

12/7 is greater than 6/13 and it's asking what numbers would be incorrect meaning less than 6/13 (unmark 12/7)

1/10 is correct since 6/13 is greater than 3 / 65 (It's what you get when you multiple 1/10 with 6/13)

Unmark 4/3

Unmark 3

and 13/13 is just equal to 6/13 (leave unmarked)

Question 4

I don't know kiddo it's been a while

<u></u>

BARSIC [14]2 years ago

4 0

The person above me is very much correct

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Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

$\text { Volume of a cylinder }=\pi r^{2} h$

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e

$\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}$

<em><u>Ratio for the volumes of two cylinders</u></em>

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}$

Cancelling the common terms, we get

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)$

Substituting we get,

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}$

Hence, the ratio of volume of two cylinders is 8 : 27

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2 years ago